Answer:
The angular velocity of the propeller is 2.22 rad/s.
Explanation:
The angular velocity (ω) of the propeller is:
Where:
θ: is the angular displacement = 10.6 revolutions
t: is the time = 30 s
Therefore, the angular velocity of the propeller is 2.22 rad/s.
I hope it helps you!
<span>Protozoa live in seas, rivers, lakes, ponds, decaying matters and soil</span>
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> = initial velocity, <em>v</em> = final velocity, <em>a</em> = acceleration, and ∆<em>x</em> = distance traveled.
So
<em>v</em>² - (15 m/s)² = 2 (6.5 m/s²) (340 m)
<em>v</em>² = 4645 m²/s²
<em>v</em> ≈ 68.15 m/s
Let m = the mass of the softball.
Then the mass of the basketball is 3m.
By definition, momentum = mass * velocity.
If both the softball and basketball move at the same velocity, v, then
Momentum of the softball = mv
Momentum of the basketball = 3mv
Answer: The momentum of the basketball is 3 times that of the softball.
