Answer:
Reduction in work in progress = $7500
Explanation:
given data
time = 10 hours
time = 15 hours
worth = $1,500
to find out
reduction in work in process value
solution
we find work in progress by this formula
work in progress = Flow rate × Cycle Time .......................1
so Initial work in progress is
Initial work in progress = (1 per hour) × 10 hours = 10
and Final work in progress is here
Final work in progress = (1 per hour) × 15 hours = 15
so
Initial work in progress value = 10 × 1500
Initial work in progress value= $15000
and
Final work in progress value =15 × 1500
Final work in progress value = $22500
so
Reduction in work in progress = $22500 - $15000
Reduction in work in progress = $7500
Answer:
Therefore I can borrow $19646.12 from E-Loan.
The interest I will pay for the loan is $1,857.88.
Explanation:
The formula of present value is
PMT = The monthly payment = $448
i= Rate of interest per period 
n = The number of month = 48 months
Therefore
≈$19646.12
Therefore I can borrow $19646.12 from E-Loan.
The interest = Paid amount - Loan amount
=$[(448×48)-19646.12]
=$1,857.88
The interest I will pay for the loan is $1,857.88.
Answer:
Loss on disposal $1,800
Explanation:
Cost of Asset 26,000
Useful life 5years
Sale proceeds 19,000
Depreciation for the year=$26,000/5=$5,200
Written Down value(WDV)=$26,000-$5,200=$20,800
Loss on Disposal= Sale proceeds- WDV=$19,000-$20,800=$1,800
It is assumed that depreciation is fully charged for the year on asset.
