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Monica [59]
2 years ago
12

A well-known transform boundary found in California is the _____. San Francisco fault, San Andreas fault, San Diego fault, OR Sa

n Jose fault?
Physics
2 answers:
Trava [24]2 years ago
7 0
San Andreas fault is the answer
SOVA2 [1]2 years ago
6 0

Answer;

San Andreas fault

A well-known transform boundary found in California is the San Andreas fault.

Explanation;

The San Andreas Fault is the most famous fault in the world.The San Andreas Fault is a place where two tectonic plates touch, the North American and Pacific Plates. The plates are rigid (or almost rigid) slabs of rock that comprise the crust and upper mantle of the Earth. It is about 700 miles long as the crow flies and about 800 miles long when its curves are measured.

-A fault is a planar crack in a rock along which slippage has taken place. Most faults are small; even microscopic; and are not important. Some faults are many miles long.

-Faults can be classified according to which of the three directions of space the rocks on either side move. When the motion is predominantly vertical, they are called dip slip faults. Dip slip faults with dips less than 45 degrees are called thrust faults.

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What is the acceleration of a car going 50 mph that slows down to rest over 10 seconds?
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3 years ago
The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared
velikii [3]

Answer:

\displaystyle a(5)=-32

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

\displaystyle v(t)=\frac{df}{dt}

And the acceleration is

\displaystyle a(t)=\frac{dv}{dt}

Or equivalently

\displaystyle a(t)=\frac{d^2f}{d^2t}

The given height of a projectile is

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Let's compute the speed

\displaystyle v(t)=-32t+238

And the acceleration

\displaystyle a(t)=-32

It's a constant value regardless of the time t, thus

\boxed{\displaystyle a(5)=-32}

3 0
3 years ago
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