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olga55 [171]
2 years ago
11

The ball in this activity could reach much greater speeds if not for the loss of energy in many different transformations. There

is one major energy loss that is causing the ball to move more slowly, what is that energy? What force is acting upon the ball to create this loss of energy?
Please help quick!

Physics
1 answer:
harkovskaia [24]2 years ago
3 0

Answer:

friction acts upon the ball when it is sliding down the slide and this action creates thermal energy

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2. a) A disc rotates about its axis at speed 25 revolutions per minute and takes 15 s to stop. Calculate the
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The statement shows a case of rotational motion, in which the disc <em>decelerates</em> at <em>constant</em> rate.

i) The angular acceleration of the disc (\alpha), in revolutions per square second, is found by the following kinematic formula:

\alpha = \frac{\omega_{f}-\omega_{o}}{t} (1)

Where:

  • \omega_{o} - Initial angular speed, in revolutions per second.
  • \omega_{f} - Final angular speed, in revolutions per second.
  • t - Time, in seconds.

If we know that \omega_{o} = \frac{5}{12}\,\frac{rev}{s}, \omega_{f} = 0\,\frac{rev}{s} y t = 15\,s, then the angular acceleration of the disc is:

\alpha = \frac{0\,\frac{rev}{s}-\frac{5}{12}\,\frac{rev}{s}}{15\,s}

\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}

The angular acceleration of the disc is \frac{1}{36} radians per square second.

ii) The number of rotations that the disk makes before it stops (\Delta \theta), in revolutions, is determined by the following formula:

\Delta \theta  = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \alpha} (2)

If we know that \omega_{o} = \frac{5}{12}\,\frac{rev}{s}, \omega_{f} = 0\,\frac{rev}{s} y \alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}, then the number of rotations done by the disc is:

\Delta \theta = 3.125\,rev

The disc makes 3.125 revolutions before it stops.

We kindly invite to check this question on rotational motion: brainly.com/question/23933120

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What the density of an object that has a volume of 20ml and mass of 3g.​
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Answer:

The equation of D = m/V

Where D = density

m = mass

and V = volume

We are solving for V, so with the manipulation of variables we multiply V on both sides giving us  

V(D) = m  

now we divide D on both sides giving us

V = m/D  

We know our mass which is 600g and our density is 3.00 g/cm^3

so

V = 600g/3.00g/cm^3 = 200cm^3  or 200mL

a cubic centimeter (cm^3) is one of the units for volume. It's exactly like mL. 1 cm^3 = 1 mL

 

If you wish to change it to L, you'd have to convert

Explanation:

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