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olga55 [171]
2 years ago
11

The ball in this activity could reach much greater speeds if not for the loss of energy in many different transformations. There

is one major energy loss that is causing the ball to move more slowly, what is that energy? What force is acting upon the ball to create this loss of energy?
Please help quick!

Physics
1 answer:
harkovskaia [24]2 years ago
3 0

Answer:

friction acts upon the ball when it is sliding down the slide and this action creates thermal energy

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The potential difference between the plates of a capacitor is 145 V. Midway between the plates, a proton and an electron are rel
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Answer:

= 2.52 x 10^ 6 m/s        

Explanation:

The force that acts on charged particles between capacitor plates =

F = (q) (Δv)  ÷ d

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          q = charge of the charged particle

         Δv = voltage

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m X a =  (q) (Δv)  ÷ d

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Likewise, the acceleration of an electron when moving towards a positively charged plate is

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s = ut + 1/2 at^2

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d/2 = 1/2 at^2

making t the subject of the formula

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put d/2 =  ut + 1/2 at^2 [proton} into t =√(d ÷ a(electron))

Initial speed, ui = √(d ÷ a(electron)) = (d/2) - (1/2) x (d) (a(proton) + a(electron))

since acceleration wasn't given in the question, lets use mass(elect

ron)  ÷ mass(proton) rather than use (a(proton) + a(electron))

Therefore, intial speed= 1/2√((e X Δv) ÷ m(electron)) (1- m(electron)/ m(proton))

   Note, e = 1.60 x 10^-19

           m(electron) = 9.11 X 10^-31

            m(proton) = 1.67  X 10^-27

Input these values into the formula above, initial speed, UI =  

           = 2.52 x 10^ 6 m/s          

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