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3 years ago

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Solid silicon and solid magnesium chloride form when silicon tetrachloride gas reacts with magnesium metal. Write a word equa- t

ion and an unbalanced formula equation. Include all of the appropriate notations.

1 answer:

antiseptic1488 [7]3 years ago

8 0

SiCl4 + 2Mg ---> 2Si + 2MgCl2

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PLEASE HELP!! Thanks! How much heat (in kJ) is required to warm 13.0 g of ice, initially at -10.0 ∘C, to steam at 111.0 ∘C? The

ZanzabumX [31]

Answer:

Approximately 39.7 kJ.

Assumptions: the specific heat capacity of water is $\rm 4.182\; J \cdot mol^{-1}$ , the melting point of water is $\rm 0\, ^{\circ} C$ , and that the boiling point of water is $\rm 100 \,^{\circ} C$ .

Explanation:

It takes five steps to convert 13.0 grams of $\rm \text{-}10.0\, ^{\circ}C$ ice to steam at $\rm 111.0\,^{\circ}C$ .

Step one: heat the 13.0 gram of ice from $\rm \text{-}10.0\, ^{\circ}C$ to $\rm 0\,^{\circ}C$ . The change in temperature would be $\rm 10.0\,^{\circ}C$ .
Step two: supply the heat of fusion to convert that 13.0 gram of ice to water.
Step three: heat the 13.0 gram of water from $\rm 0\,^{\circ}C$ to $\rm 100\,^{\circ}C$ . The change in temperature would be $\rm 100\,^{\circ}C$ .
Step four: supply the heat of vaporization to convert that 13.0 gram of water to steam.
Step five: heat the 13.0 gram of steam from $\rm 100\,^{\circ}C$ to $\rm 111.0\,^{\circ}C$ . The change in temperature would be $\rm 11.0\,^{\circ}C$ .

<h3>Energy required for step one, three, and five</h3>

The following equation gives the amount of energy $Q$ required to raise the temperature of an object by a $\Delta T$ :

$Q = c \cdot m \cdot \Delta T$ .

In this equation,

$c$ is the specific heat of this substance,
$m$ is the mass of the substance, and
$\Delta T$ is the change in the temperature of the object.

Assume that there's no mass loss in this whole process. The value of $m$ would stay the same at $13.0\; \rm g$ .

$\begin{aligned}& &&\text{Energy required for raising temperature} \cr &=&& c(\text{Ice}) \cdot m \cdot \Delta(\text{Ice}) \cr & && + c(\text{Water}) \cdot m \cdot \Delta(\text{Water})\cr & && + c(\text{Steam}) \cdot m \cdot \Delta(\text{Steam}) \cr & = && (2.09 \times 13.0 \times 10) \cr & && + (4.182 \times 13.0 \times 100) \cr & &&+ ( 2.01 \times 13.0 \times 10) \cr & = && 5969.6\;\rm J \cr & = && 5.969\; \rm kJ\end{aligned}$ .

<h3>Energy required for step two and four</h3>

The equations for the energy of fusion and energy of vaporization are quite similar:

$E(\text{Fusion}) = n \cdot \Delta H_\text{Fusion}$ .

$E(\text{Vaporization}) = n \cdot \Delta H_\text{Vaporization}$ .

where $n$ is the number of moles of the substance.

Look up the relative atomic mass of oxygen and hydrogen from a modern periodic table:

H: 1.008,
O: 15.999.

Hence the molar mass of water:

$M(\rm H_2O) = 2\times 1.008 + 15.999 = 18.015\; g \cdot mol^{-1}$ .

Number of moles of $\rm H_2O$ molecules in $\rm 13.0\; g$ :

$\displaystyle n = \frac{m}{M} \approx 0.721621\; \rm mol$ .

$\begin{aligned}& &&\text{Energy required for phase changes} \cr &=&& n \cdot \Delta H_\text{Fusion} \cr & &&+n \cdot \Delta H_\text{Vaporization} \cr & = &&0.721621 \times 6.02 + 0.721621 \times 40.7 \cr & = &&33.7\; \rm kJ \end{aligned}$

<h3>Energy required for all five steps, combined</h3>

$5.969\; \rm kJ + 33.7\; \rm kJ \approx 39.7\; \rm kJ$ .

8 0

3 years ago

Gina made 9{,}350 \text{ mL}9,350 mL9, comma, 350, space, m, L of chicken noodle soup. She packed 1.8 \text{ L}1.8 L1, point, 8,

RoseWind [281]

Answer:

$7,550\ mL$

Explanation:

Remember that

$1\ L=1,000\ mL$

To convert L to mL multiply by 1,000

we know that

Gina made 9,350 mL

She packed 1.8 L of the soup in her kids' lunches

She froze the rest of the soup

step 1

Convert L to mL

$1.8\ L=1.8(1,000)=1,800\ mL$

step 2

To find out how many milliliters of soup did Gina have left to freeze, subtract 1,800 mL from 9,350 mL

$9,350-1,800=7,550\ mL$

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4 years ago

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State three acids, bases, and Salts commonly used in therapeutic processes

Delvig [45]

Acetic acid, phosphoric acid, hydrochloric acid.

sodium bicarbonate, magnesium hydroxide, aluminum hydroxide

calcium carbonate, sodium bicarbonate, magnesium sulfate.

3 0

3 years ago

What is the mass percentage of carbon in 5.000 G of sucrose

Crank

17) 8.4 / 20 x 100

18) 20 . 0.5150

19) 6,50% because (as you said) the law of definite proportions states that regardless of the amount, a compound is always composed of the same elements in the same proportion by mass

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3 years ago

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What is the mole ratio of d to a in the generic chemical reaction 2a+b-- c+3d?

barxatty [35]

Answer: D : A is 3 : 2.

Explanation:

The law of definite proportion is being used here. The law states that a given compound always has the same proportion of its constituent elements by mass.

2a + b = c + 3d

This actually means that, two moles of “a” react with a mole of “b” to produce a mole of “c” and 3 moles of “d”

Using the concept of stoichiometry coefficients of d and a

d:a = 3:2

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3 years ago

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