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PilotLPTM [1.2K]
3 years ago
8

A sample of octane (c8h18 that has a mass of 0.750 g is burned in a bomb calorimeter. as a result, the temperature of the calori

meter increases from 21.0°c to 41.0°c. the specific heat of the calorimeter is 1.50 j/(g °c, and its mass is 1.00 kg. how much heat is released during the combustion of this sample? use .
Chemistry
2 answers:
timurjin [86]3 years ago
7 0
In a closed system, heat should be conserved which means that the heat produced in the calorimeter is equal to the heat released by the combustion reaction. We calculate as follows:

Heat of the combustion reaction = mC(T2-T1)
                                                          = 1 (1.50) (41-21)
                                                          = 30 kJ
GenaCL600 [577]3 years ago
3 0

Answer:

30 kJ is released during the combustion of this sample.

Explanation:

Heat released during combustion = Heat gained by calorimeter

Mass of calorimeter= m = 1.00 kg=1000 g

Change in temperature of the calorimeter = ΔT = 41.0 °C - 21.0 °C =20.0 °C

Specific heat if calorimeter = c = 1.50 J/g °C

Heat released during combustion = Q

Q=mc\Delta T

Q=1000.00 g\times 1.50 J/g ^oC\times 20.0 ^oC=30,000 =30 kJ

30 kJ is released during the combustion of this sample.

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Equal amounts of N2 and O2 are added, under certain conditions, to a closed container. Which changes occur in the reverse reacti
geniusboy [140]
1) The forward reaction is N2 (g) + O2 (g)  → 2NO

(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.

2) The equiblibrium equation is

  N2 (g) + O2 (g)  ⇄ 2NO

3) Then, the reverse reaction is

2NO → N2(g) + O2(g)

Answer: 2NO → N2(g) + O2(g)
4 0
3 years ago
A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
2 years ago
Calculate the maximum volume in ml of 0.15M HCl that each of the following antacid formulations would be expected to neutralize.
vlada-n [284]

a. 34 mL; b. 110 mL

a. A tablet containing 150 Mg(OH)₂


Mg(OH)₂ + 2HCl ⟶ MgCl₂ + 2H₂O


<em>Moles of Mg(OH)₂</em> = 150 mg Mg(OH)₂ × [1 mmol Mg(OH)₂/58.32 mg Mg(OH)₂

= 2.572 mmol Mg(OH)₂


<em>Moles of HCl</em> = 2.572 mmol Mg(OH)₂ × [2 mmol HCl/1 mmol Mg(OH)₂]

= 5.144 mmol HCl


Volume of HCl = 5.144 mmol HCl × (1 mmol HCl/0.15 mmol HCl) = 34 mL HCl


b. A tablet containing 850 mg CaCO₃


CaCO₃ + 2HCl ⟶ CaCl₂ + CO₂ + H₂O


<em>Moles of CaCO₃</em> = 850 mg CaCO₃ × [1 mmol CaCO₃/100.09 mg CaCO₃

= 8.492 mmol CaCO₃


<em>Moles of HCl</em> = 8.492 mmol CaCO₃ × [2 mmol HCl/1 mmol CaCO₃]

= 16.98 mmol HCl


Volume of HCl = 16.98 mmol HCl × (1 mL HCl/0.15 mmol HCl) = 110 mL HCl


5 0
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Is carbon dioxide a polar molecule? Why or Why Not?
irinina [24]

Explanation:

Carbon dioxide isn't a polar molecule because

same nature of charge appears in opposite direction which cancel each other. So, carbon dioxide is non-polar molecule.

6 0
3 years ago
How do the independent and dependent variables in an experiment compare?
DENIUS [597]
An independent variable<span> is the </span>variable<span> that is changed or controlled in a scientific </span>experiment<span> to test the effects on the </span>dependent variable<span>. </span>
4 0
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