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Serjik [45]
3 years ago
14

Calculate the percent saturated fat in the total fat in butter

Chemistry
1 answer:
Talja [164]3 years ago
7 0
About 63% of the fat in butter is saturated fat
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What will be the effect on the solubility of BaF2 if the following changes are made: increasing temperature; adding NaF; adding
borishaifa [10]

In BaF₂ the solubility will decreases on adding NaF

the solubility will increases on adding HCl

<h3>SOLUBILITY OF BARIUM FLUORIDE</h3>
  • Increase in temperature will increase the solubility of the solid.
  • By adding NaF - decrease the solubility of BaF₂
  • By adding HCl - increase the solubility of BaF₂

<h3>BARIUM FLUORIDE</h3>
  • It is colourless solid that occur as rare mineral
  • It is corroded by moisture
  • It is used in window of IR spectroscopy

Hence the barium fluoride the solubility decreases on adding NaF and increases on adding HCl.

Learn more about the solubility on

brainly.com/question/6841847

#SPJ4

3 0
2 years ago
Complete and balance the following redox reaction in acidic solution As2O3(s) + NO3- (aq) → H3AsO4(aq) + N2O3(aq)
scoray [572]

Answer:

As_{2}O_{3}(s)+2NO_{3}^{-}(aq)+2H_{2}O(l)+2H^{+}(aq)\rightarrow 2H_{3}AsO_{4}(aq)+N_{2}O_{3}(aq)

Explanation:

Oxidation: As_{2}O_{3}(s)\rightarrow H_{3}AsO_{4}(aq)

  • Balance As: As_{2}O_{3}(s)\rightarrow 2H_{3}AsO_{4}(aq)
  • Balance H and O in acidic medium: As_{2}O_{3}(s)+5H_{2}O(l)\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)
  • Balnce charge: As_{2}O_{3}(s)+5H_{2}O(l)-4e^{-}\rightarrow 2H_{3}AsO_{4}(aq)+4H^{+}(aq)......(1)

Reduction: NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)

  • Balance N: 2NO_{3}^{-}(aq)\rightarrow N_{2}O_{3}(aq)
  • Balance H and O in acidic medium: 2NO_{3}^{-}(aq)+6H^{+}(aq)\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)
  • Balance charge: 2NO_{3}^{-}(aq)+6H^{+}(aq)+4e^{-}\rightarrow N_{2}O_{3}(aq)+3H_{2}O(l)......(2)

Equation (1)+Equation (2) gives-

As_{2}O_{3}(s)+2NO_{3}^{-}(aq)+2H_{2}O(l)+2H^{+}(aq)\rightarrow 2H_{3}AsO_{4}(aq)+N_{2}O_{3}(aq)

3 0
3 years ago
Read 2 more answers
If you burn 53.8 g of hydrogen and produce 481 g of water, how much oxygen reacted?
olga2289 [7]
The reaction:
2 H 2 + O 2 → 2 H 2 O
2 Hydrogen molecules react with 1 Oxygen molecule to create 2 molecules of water. 
We have to convert 53.8 g of Hydrogen into moles:
53.8 : 2.02 g / moles = 26.63 moles
2 moles H 2 ↔ 1 mole O 2
26.63 moles H 2  ↔ 13.32 moles O 2
Mass ( O 2 ) = 13.32 moles · 32 g/moles = 426.2 g
Answer: 426.2 grams of Oxygen.

4 0
3 years ago
Bela made scrambled eggs while camping. She placed the eggs in a pan on the grill, then turned on the flame to apply heat to the
Alina [70]

Answer: Temperature.

7 0
3 years ago
Read 2 more answers
Answer the following questions: On a 10-fold dilution of a weak acid, the pH will ______________ . On a 10-fold dilution of a we
Scorpion4ik [409]

Answer:

i) increase

ii) decrease

iii) remain the same

iv) No, because it dissociates completely.

Explanation:

On a 10-fold dilution of a weak acid, the pH will increase because the concentration of hydrogen ions will decrease thereby increasing the pH to close to that of water.

On a 10-fold dilution of a weak base, the pH will decrease due to the removal of hydroxide ions from the solution. This results in the solution having a H closer to that of water.

If one adds a very small amount of strong base to a buffered solution, the pH will remain constant because a buffer solution acts to withstand any change to its pH on the addition of small quantities of either an acid or a base.

A buffer solution cannot be made with a strong acid because thy undergo complete dissociation. Therefore, any small addition of base or acid will result in very large changes in the pH of the solution. A buffer solution is made with a weak acid and its conjugate base or a weak base and its conjugate acid.

6 0
3 years ago
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