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laila [671]
2 years ago
9

Benny wonders why when he presses his finger against a map nothing

Chemistry
1 answer:
AnnyKZ [126]2 years ago
6 0

The pressure exerted on a surface by an object increases as the surface area of contact decreases.

Explanation:

Pressure measures the amount of force exerted per a given area of an object. From this definition, the surface area of the object and force applied, affects the pressure applied.

As Benny presses his finger against a map, nothing happens to the map because the force applied is affected by the increased surface area of his finger. However as he presses a thumbtack into the map using the same force the tack will probably poke a hole in the map because the small( decreased) surface area of the sharp point of the thumbtack produces a much larger pressure on the map than the area of Benny finger. I hope this helps, thanks!

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A flexible container at an initial volume of 8.15 l contains 6.51 mol of gas. more gas is then added to the container until it r
kirill [66]
<span>A </span>flexible container<span> at an </span>initial volume<span> of 7.14 </span>L contains<span> 7.51 </span>mol<span> of </span>gas<span>. </span>More gas<span> is</span>then added<span> to the </span>container until<span> it </span>reaches<span> a </span>final volume<span> of 17.7 </span>L<span>. </span>Assuming<span> the </span>pressure<span> and</span>temperature<span> of the </span>gas remain constant<span>, </span>calculate<span> the </span>number<span> of </span>moles<span> of </span>gas added<span> to the </span>container<span>.</span>
3 0
3 years ago
At a certain temperature, a mixture of 2 gases, 11.2 g of oxygen and 104.75 of krypton exert a total pressure of 4.25 atm. What
ki77a [65]

Answer:

Pressure of O₂ = 0.93 atm

Pressure of krypton = 3.32 atm

Explanation:

This problem can be solved by using Dalton's Law of Partial Pressures, which states that the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture.

Pₐ = Xₐ * Ptotal

P ₐ  - the partial pressure of component  a  

χ ₐ   - its mole fraction in the mixture

P total  - the total pressure of the mixture

The moles of the two gases are:

moles of O₂ = 11.2/32 = 0.35 moles

moles of krypton = 104.75/83.8 = 1.25 moles

Total moles = 1.25 + 0.35 = 1.6 moles

Xₐ = number of moles of a /total moles in mixture

Pressure of O₂ = 0.35/1.6 *4.25 = 0.93 moles

Pressure of krypton = 1.25/1.6 *4.25 = 3.32 moles

4 0
3 years ago
A certain first-order reaction (A→products) has a rate constant of 8.10×10−3 s−1 at 45 ∘C. How many minutes does it take for the
stira [4]

Answer:

The answer is 5.7 minutes

Explanation:

A first-order reaction follow the law of Ln [A] = -k.t + Ln [A]_{0}. Where <em>[A]</em> is the concentration of the reactant at any <em>t</em> time of the reaction, [A]_{0} is the concentration of the reactant at the beginning of the reaction and <em>k</em> is the rate constant.

Dropping the concentration of the reactant to 6.25% means the concentration of A at the end of the reaction has to be [A]=\frac{6.25}{100}.[A]_{0}. And the rate constant (<em>k</em>) is 8.10×10−3 s−1

Replacing the equation of the law:

Ln \frac{6.25}{100}.[A]_{0} = -8.10x10^{-3}s^{-1}.t + Ln[A]_{0}

Clearing the equation:

Ln [A]_{0}.\frac{6.25}{100} - Ln [A]_{0} = -8.10x10^{-3}s^{-1}.t

<em>Considering the property of logarithms: </em>Ln A - Ln B = Ln \frac{A}{B}

Using the property:

Ln \frac{[A]_{0}}{[A]_{0}}.\frac{6.25}{100} = -8.10x10^{-3}s^{-1}.t

Clearing <em>t </em>and solving:

t = \frac{Ln \frac{6.25}{100} }{-8.10x10^{-3}s^{-1} } = 342.3s

The answer is in the unit of seconds, but every minute contains 60 seconds, converting the units:

342.3x\frac{1min}{60s} = 5.7min

6 0
3 years ago
Use the following information to determine the empirical formula if a compound is found to have 18.7% Li, 16.3% C, and 65.5% O A
Elina [12.6K]

Answer:

The empirical formula is Li2CO3

Explanation:

Step 1: Data given

Suppose the mass of the compound = 100 grams

The compound contains :

18.7% Li = 18.7 grams of Li

16.3 % C = 16.3 grams of C

65.0% O = 65.0 grams of O

Total = 100%

Molar mass of Li = 6.94 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate moles

Moles = Mass / molar mass

Moles Li = 18.7 grams / 6.94 g/mol = 2.65 moles

Moles C = 16.3 grams / 12.01 = 1.36 moles

Moles O = 65.0 grams / 16.0 g/mol = 4.06 moles

Step 3: Calculate the mol ratio

We divide by the smallest number of moles

Li: 2.65/1.36 ≈ 2

C: 1.36/1.36 = 1

O: 4.06/1.36 ≈ 3

The empirical formula is Li2CO3

3 0
3 years ago
A piece of metal has a mass of 500 g and a volume of 5 cm3. What is its specific gravity?
Vadim26 [7]
I believe the answer is 100. Hope this helps. (ノ◕ヮ◕)ノ*:・゚✧
density = mass/volume.

3 0
3 years ago
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