Answer:
0.83 m/s
Explanation:
FIrst of all, we have to find the time of flight, i.e. the time the baseball needs to reach the ground. This can be done by using the equation for the vertical motion:
where
h is the initial height
u = 0 is the initial vertical velocity
g = 9.8 m/s^2 is the acceleration of gravity
t is the time
Substituting h = 1.8 m and solving for t,
We know that the horizontal distance travelled by the ball is
d = 0.5 m
Therefore, we can find the horizontal velocity (which is constant during the whole motion):
Could have gotten tired after the first trial. ? i’m not sure if that’s it
Answer:
also tripled, factor of 3
Explanation:
equation of momentum is p = m * v , where p=momentum, m=mass, and v=velocity
if m is unchanged
p1 = m1 *v1
p2 = m2 *v2
m1 = m2 and v2 = 3*v1
p2 = m1 * 3v1 = 3*p1, tripled momentum
I would say d if I remember right I think that’s what I put and got right sorry if it’s wrong
Answer:
a) 0.05719 km/s^2
b) 0.00921 km/s^2
Explanation:
average acceleration can be calcuated as follows
a)
- In the initial time (
), just before of race start the rocket is at rest. So 
.
- After 3.22 s the rocket reach 663 km/h, So 
and the 
. We convert units from km/h to km/s to have the same time units (seconds) the velocity would be:
(take into accoun that 1 h=3600 s)
and acceleration is:
b)
acceleration while stopping is calculate with the same formula but now
-we define the initial time () the instant just before begining the stopping. At this instant the velocity is 663 km/h which is the same as 0.18467 km/s.
-After 20 seconds the rocket stops. So tex]t_f=20 s[/tex] and 
So, acceleration is:
