Time taken by proton to complete one complete circular orbit= 7.28 x 10⁻⁸ s
Explanation:
For proton, the centripetal force required for circular motion is provided by the magnetic force,
so Fm= Fc
q v B = m v²/r
m= mass of charged particle
v= velocity
B =magnetic field
q= charge
r= radius of circular path
v= q B r/m
now v= r ω
ω= angular velocity
ω r = q B r /m
ω=q B /m
now ω= 2π/T where T =time period
so 2π/T=q B/m
T= 2 πm/q B
T= 2π (1.67 x 10⁻²⁷)/ [( 1.6 x 10⁻¹⁹)* (0.9)]
T= 7.28 x 10⁻⁸ s
Answer:
B = 4/3 ( i + j + k )
Explanation:
I = 3 k
L = 5 x 10⁻² m
F = - 0.2 i + 0.2 j
Let magnetic field be B
B = B₁ i + B₂ j + B₃ k
F = L ( I x B )
= 5 x 10⁻² 3 k x ( B₁ i + B₂ j + B₃ k )
= 15 x 10⁻² B₁ j - 15 x 10⁻² B₂ i
Given
F = - 0.2 i + 0.2 j
equating equal terms
15 x 10⁻² B₂ = .2
15 x 10⁻² B₁ = .2
B₁ = .02 / 15 x 10⁻² = 20 / 15 N
B₂ = .02 / 15 x 10⁻² = 20 / 15 N
Now wire is rotated so that current flows in positive x direction
I = 3 i
F = . 2 k
F = L ( I x B )
= 5 x 10⁻² x 3 i x ( B₁ i + B₂ j + B₃ k )
= 15 x 10⁻² B₃ k
15 x 10⁻² B₃ = .2
B₃ = .2 /15 x 10⁻²
B₃ = 20 /15
B = B₁ i + B₂ j + B₃ k
20 /15 9 ( i + j + k )
B = 4/3 ( i + j + k )
Adiabatic process is that process in which heat of a closed system will remain conserved or we can say that system can not exchange its thermal energy from its surrounding
So here from 1st law of thermodynamics we can say
since we know that
so we will have
so we have
so here correct answers are
<em>A. -ΔU = W </em>
<em>B. Heat is constant. </em>
Answer:
No not at all. A car speeding up is an example of acceleration.
Answer:
1. 2 N to the left
2. To the left.
Explanation:
1. Determination of the net force.
Force applied to the right (Fᵣ) = 18 N
Force applied to the left (Fₗ) = 20 N
Net force (Fₙ) =?
The net force acting on the book can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 20 – 18
Fₙ = 2 N to the left
Thus, the net force acting on the book is 2 N to the left
2. Determination of the direction.
From 1 above, the net force acting on the book is 2 N to the left. This simply means that the book will move to the left direction.
