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drek231 [11]
3 years ago
13

The ions in most ionic compounds are organized into a

Chemistry
1 answer:
Igoryamba3 years ago
5 0
They are organized into crystals hope i helped
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What is the theoretical yield of moles of hydrogen that can be produced from 0.032g of MG?
Ugo [173]

Answer:

1.31x10⁻³ moles of H₂

Explanation:

This is the equation:

Mg(s)  +   2H₂O (g)   →   Mg(OH)₂ (aq)   +    H₂(g)

Ratio is 1:1, so 1 mol of Mg is needed to produce 1 mol of H₂

Mass / Molar mass = Mol

0.032 g / 24.3 g/m = 1.31x10⁻³ moles

1.31x10⁻³ moles of H₂(g)

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The first law of thermodynamics is a restatement of the
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the law of thermodyanamic is the restatement of the law of conservation of energy

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What do radio waves and gamma rays have in common?
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Answer: The sequence from longest wavelength (radio waves) to shortest wavelength (gamma rays) is also a sequence in energy from lowest energy to highest energy. ... The energy carried by a radio wave is low, while the energy carried by a gamma ray is high. Different materials can block different types of light.

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3 years ago
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How are gems different from regular minerals? Gems are softer than regular minerals. Regular minerals are more beautiful than ge
just olya [345]
The definition of a gem is "a precious stone, cut and polished for jewelry. They are all minerals. Some highly desirable gemstones may not be suitable for jewelry, yet be very collectible, like sphene. Others, like those in the corundum family, are prized for color and hardness, like emeralds and diamonds. Further, some common minerals, when polished, make beautiful pieces. With all that said, i woukd go with rarer.
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3 years ago
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a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g
leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

Solution :

By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

Therefore , percentage of Na by mass in NaBr will be same for every amount .

Percentage of Na in 9.77 g NaBr is 22.34 % too .

Gram of Na = 9.77\times \dfrac{22.34}{100}=2.18\ g .

Hence , this is the required solution .

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