The equation:
Pb(NO3)2 + K2SO4 = PbSO4 + 2KNO3
The ionic equation:
Pb(NO3)2 + K2SO4 = PbSO4 + 2KNO3
The ionic equation:
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1 answer:
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The given question is incomplete. The complete question is:
Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer: 0.0484 g
Explanation:
where Q= quantity of electricity in coloumbs
I = current in amperes = 0.920 A
t= time in seconds = 47.0 sec
96500 Coloumb of electricity electrolyzes 1 mole of Ag
43.24 C of electricity deposits = of Ag
Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g