Answer:
Acceleration=
Speed=0.67 m/s
Explanation:
We are given that
Horizontal force=F=20 N
Mass of box=m=40 kg
We know that
Acceleration=
Using the formula
Acceleration of box=
The acceleration of the box=
Initial velocity=u=0
Force=F=30 N
Distance=s=0.3 m
Substitute the values
Hence, the speed of the box after it has been pulled a distance of 0.3 m=0.67 m/s
Answer:
It is half the field strength at 0.5cm
Explanation:
1.
a. The one with the greater volume will rise slower than the one of the left.
b. It would make the readings high than they were before.
b. it will make the readings higher than they were before
Answer:
a) 3.6 sec
b) 17.7 m/s
c) 17.7 m/s
d) 63.6 m
Explanation:
y = (25sin45)t - 4.9t^2 =17.7t - 4.9t^2
a) to find hang time set y = 0
4.9t^2 = 17.7t or t = 3.6 sec
b) vx = 25cos45 = 17.7 m/s
c) vy = 25sin45 = 17.7 m/s
d) To find the range R, use the results in (a) and (b) into the equation R = vxt:
R = (17.7 m/s)(3.6 sec) = 63.6 m
