Answer:
a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s
Explanation:
a)
- As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
- This means that we can use the kinematic equations for displacements along both axes.
- In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:
- In the y-direction, as no acceleration is acting on the skateboarder, we can write the following displacement equation:
- For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:
b)
- From (2) we can get the position on the y-axis (displacement from the origin) as follows:
c)
- In the x- direction, we can find the component of the velocity along this direction, as follows:
- Replacing by the values, we have:
d)
- As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we have:
vfy = voy = -4 m/s
The answer is A. They are both processes in which water is changed into water vapor.
The force produced on a particle of charge q by an electric field of intensity E is
in our problem, the force is F=5.0 N while the charge is q=2.0 C, so we can find the intensity of the electric field:
The relationship between electric field intensity and potential difference
between two points A and B is
where d is the distance between the two points. By using d=6.0 m, we find
where the negative sign means that the initial point, VA, is at higher potential than the final point VB.
Answer:
Because the effect is not big enough to be noticeable.
Explanation:
The light is bent by gravitational fields, but the bend is not that big unless we are talking about objects with a massive amount of mass. To be noticed the bent, you need to stay far away from the object that causes the blend and the object also needs to be far away from the source of the light. For example, you can observe the blend in the light of a far-away star when the light travels close to the sun to reach earth, and the deflection will be around 1.75 arc-seconds. The deflection occurs also with light beams on the earth but the effect is too small to be taken into consideration.