Gamma rays<span> are produced in the disintegration of radioactive atomic nuclei and in the decay of certain subatomic particles. ... When an unstable atomic nucleus decays into a more stable nucleus (see radioactivity), the “daughter” nucleus is sometimes produced in an excited state.</span>
Answer:
The work done by the electric force is =
The potential of the starting point with respect to the end point is
The magnitude of E
Explanation:
Looking at this we can see that the work done by the electric force is equal to the kinetic energy this is because on the electric field is uniform and that the work done resulted in motion.
Mathematically
Where is the potential difference
q is the charge whose value i given as =
W is the workdone whose value is obtained as =
Substituting
Mathematically
Where E is the electric field strength
d is the distanced moved and it is given as 6.00 cm = 0.06 m
Making E the subject of the formula
Answer:
<em>1.07m/s²</em>
Explanation:
From the question we are given the following
applied force Fapp = 450N
mass of the safe m = 100kg
Weight of the safe W = 980N
coefficient of kinetic friction n = 0.35
Required
Acceleration of the safe
According to Newton's second law
\sum Fx = ma
Fapp - Ff = ma
Ff is the frictional force
Fapp - nmg = ma
450 - 0.35(100)(9.8) = 100a
450 - 343= 100a
107 = 100a
a = 107/100
a = 1.07m/s²
<em>Hence the acceleration of the safe is 1.07m/s²</em>
Answer:
,Assume that the average volume of an adult human body is one-tenth
cubic meter (0.10 m) and that there are two billion (2.0 x 109)
adults in the world.
a. What would be the total volume of all the adults in the world?
b. Compute the length of one edge of a cubic container that has a
volume equal to the volume of all the adults in the world.
Answer:
e). The ratio is not given
Explanation:
<u>Capacitance of a capacitor</u>
The expression for the capacitance of a capacitor with di electric material is given as
C=KεA/d
where
ε=permittivity of di electric
C= capacitance in farads
A= Area of plate
d= separating distance
K= dielectric constant
let the distance in capacitor B be 1mm
therefore the distance in A is 0.5mm
For the first (A) capacitor
C1=8εA/0.5
C1=16εA
For the Second (B) capacitor
C2=8εA/1
C2=8εA
the ratio of the capacitance of A to B
=C1/C2
=16εA/8εA
=2/1
=2