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3 years ago

Please help me with this i am so!! stuck

2 answers:

6 0

If small objects can be anything, basically anything goes! People could go, ants could go, they are really tiny, use your imagination, and you could think of many possibilities!

Alex17521 [72]3 years ago

4 0

The question seems kind of squishy.

The smallest objects are also the most numerous in the
whole universe. Those are the Hydrogen atoms.

The most numerous objects that are big enough for us to see
are the stars, but I'm not going to say that those are the answer.
Stick with me here, and follow my reasoning.

The Kepler space telescope is discovering so many planets
orbiting other stars outside our solar system, that it's beginning
to look like MOST stars have planets.

Stars are bigger. Planets are smaller. If most stars have planets,
then the most numerous objects that compose much of the universe
are the planets ! (plus maybe their moons too)

Does this make any sense to you ?

Now I have to ask YOU a question:
Are there any choices for answers to this question
that you're not telling us about ?

You might be interested in

A car is making a 40 mi trip. It travels the first half of the total distance 20.0 mi at 18.00 mph and the last half of the tota

sukhopar [10]

Answer: The average speed is 27,24 mph (exactly 1008/37 mph)

Explanation:

This is solved using a three rule: We know the speeds and the distances, what we can obtain from it is the time used. It is done like this:

1h--->18mi

X ---->20 mi, then X=20mi*1h/18mi= 10/9 h=1,111 h

1h--->56mi

X ---->20 mi, then X=20mi*1h/56mi= 5/14 h=0,35714 h

Then the average speed is calculated by taking into account that it was traveled 40mi and the time used was 185/126 h=1,468 h and since speed is distance over time we get the answer. Average speed= 40mi/(185/126 h)=1008/37 mph=27,24 mph.

5 0

3 years ago

A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of

Sholpan [36]

$F=ma$
where:
F - force
m - mass
a - acceleration

We transform this formula to get a:
$a= \frac{F}{m}$
$a=\frac{2}{10}\frac{N}{kg}=0.2\frac{m}{s^{2}}$

4 0

3 years ago

Read 2 more answers

Consider the expression below. Assume m is an integer. 6m(2m + 18) Enter an expression in the box that uses the variable m and m

Anika [276]

6x2=12m
6x18=108
12m+108
Simplified: m+9 bc 12/12 and 108/12

8 0

3 years ago

A box weighing 43.2 N is pulled horizontally until it slides uniformly lat a constant

GREYUIT [131]

Your diagram should include four forces:

• the box's weight, pointing down (magnitude w = 43.2 N)

• the normal force, pointing up (mag. n)

• the applied force, pointing the direction in which the box is sliding (mag. p = 6.30 N, with p for "pull")

• the frictional force, pointing oppoiste the applied force (mag. f )

The box is moving at a constant speed, so it is inequilibrium and the net forces in both the vertical and horizontal directions sum to 0. By Newton's second law, we have

n + (-w) = 0

and

p + (-f ) = 0

So then the forces have magnitudes

w = 43.2 N

n = w = 43.2 N

p = 6.30 N

f = p = 6.30 N

5 0

3 years ago

A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision.

Pavel [41]

Answer:

(a) nearsighted

(b) diverging

(c) the lens strength in diopters is 1.33 D, and considering the convention for divergent lenses normally prescribed as: -1 33 D

Explanation:

(a) The person is nearsighted because he/she cannot see objects at distances larger than 75 cm.

(b) the type of correcting lens has to be such that it counteracts the excessive converging power of the eye of the person, so the lens has to be diverging (which by the way carries by convention a negative focal length)

$f=\frac{1}{d} =\frac{1}{0.75} = 1.33\,D$

So it would normally be written with a negative signs in front indicating a divergent lens.

7 0

3 years ago