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horsena [70]
3 years ago
12

Iron has a density of 7.9 g/cm3. How much mass is in a 10 cm3 sample of iron?

Physics
2 answers:
Stolb23 [73]3 years ago
8 0
7.9 g/cm3 means that iron weighs 7.9 grams per cubic centimeter. Ten cubic centimeters of iron would weigh ten times as much as one cubic centimeter or iron, or 79 grams.<span>


</span>
DedPeter [7]3 years ago
6 0

Answer: The mass of iron is 79 grams.

Explanation:

To calculate mass of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Density of iron = 7.9g/cm^3

Volume of iron= 10cm^3     (Conversion factor: 1cm^3=1mL  )

Putting values in above equation, we get:

7.9g/cm^3=\frac{\text{Mass of iron}}{10cm^3}\\\\\text{Mass of iron}=79g

Hence, the mass of iron is 79 grams.

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What do these letters stand for<br> P=mv
victus00 [196]

Answer:

The equation for momentum of a piece of matter.

In either case, the momentum would be less than a linebacker hitting you at full speed. The equation for momentum is written: p = mv where p stands for momentum. That is, mass times velocity equals momentum.

Explanation:

Hope This Helps

Have A Great Day

4 0
2 years ago
How can we protect space shuttles or astronauts from space radiation in the absence of the atmospheric layer?
Arisa [49]
Earth's protective magnetic bubble, called the magnetosphere, deflects most solar particles, but in the absence of atmospheric layer, Polyethylene is a good shielding material because it has high hydrogen content, and hydrogen atoms are good at absorbing and dispersing radiation.

The Earth’s atmospheres are kept in place by gravity. The air near the ground is pulled on by gravity and compressed by the air higher in the sky. This causes the air near the ground to be denser and creating different layers with different qualities in which are the atmosphere.

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7 0
3 years ago
A student uses the circuit shown to determine the resistance of two identical resistors.
Ivanshal [37]

Answer:

B. 0.552

Explanation:

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7 0
2 years ago
If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the
kodGreya [7K]

Answer:

a)

v = 4.048 *10^6 m/s

b)  

Angular frequency =  1.92 * 10^7

Explanation:

As we know

v =  \frac{qBr}{m}

q is the charge on the electron = 3.2 * 10^{-19} C

B is the magnetic field in Tesla = 0.4 T

r is the radius of the circle = 0.21 m

mass of the electrons = 6.64 * 10^{-27} Kg

a)

Substituting the given values in above equation, we get -

v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6m/s

b)  

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\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7

8 0
2 years ago
Use the following photoelectric graph to answer the following question:
klio [65]
The photoelectric effect is obtained when you shine a light on a material, resulting in the emission of electrons.

The kinetic energy of the electrons depends on the frequency of the light:
K = h(f - f₀)

where:
K = kinetic energy 
h = Planck constant
f = light frequency
f₀ = threshold frequency

Rearranging the formula in the form y = m·x + b, we get:
K = hf - hf₀
where:
K = dependent variable
f = <span>indipendent variable
h = slope
hf</span>₀ = y-intercept

Every material has its own threshold frequency, therefore, what stays constant for all the materials is h = Planck constant (see picture attached).

Hence, the correct answer is C) the slope.

5 0
3 years ago
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