What happens to the pressure in all parts of a confined fluid if the pressure in one part is increased?

Physics

1 answer:

Sauron [17]3 years ago

4 0

Answer:

The pressure will be transmitted equally to all other parts of the confined fluid causing a general increase in pressure throughout the container.

Explanation:

This is in line with pascal's law of pressure which states that the pressure exerted on a given mass of fluid is transmitted undiminished to other parts of the fluid.

You might be interested in

A force of 1 newton will cause a mass of 1 kg to have an acceleration of 1 m/s^2. If a force of 5 newtons is applied to a mass o

nignag [31]

For any force and any mass, the acceleration is always

(the strength of the force) divided by (the mass) .

If a force of 5 newtons is applied to a mass of 5 kg, the acceleration will be

(5 Newtons) / (5 kg) = <em>1 m/s²</em>

7 0

3 years ago

A cart travels 4.00 meters east and then4.00 meters north. determine the magnitude ofthe cart’s resultant displacement.

gogolik [260]

^
|
|
|
----------->|

Square root of (4^2 + 4^2) = 4*squareRoot(2)

7 0

3 years ago

A 235 kg motorcycle moves with a velocity of 7 m/s. What's it's kenetic energy?

antiseptic1488 [7]

The non-relativistic formula for low speed v < 0.1c is:

K.E = 0.5mv^2 = 0.5 * 235 * (7)^2 = 5757.5 J

7 0

3 years ago

To practice problem-solving strategy 26.1 resistors in series and parallel. two bulbs are connected in parallel across a source

hichkok12 [17]

Emf e = 11
r 1 = 3.0
r 2 = 3.0
r 3 = ?

The two in parallel are equivalent to 3 • 3/6 = 1.5 Ω
To have 2.4 volts across them, the current is I = 2.4/1.5 = 1.6 amps. and the unknown R = (11–2.4) / 1.6 = 5.375 Ω or 5.4 Ω

3 0

3 years ago

A boat heads directly across a river. Its speed relative to the water is 3 m/s. It takes it 539 seconds to cross, but it ends up

nikklg [1K]

Answer:

3.24 m/s

Explanation:

Suppose that the boat sails with velocity (relative to water) direction being perpendicular to water stream. Had there been no water flow, it would have ended up 0m downstream

Therefore, the river speed is the one that push the boat 662 m downstream within 539 seconds. We can use this to calculate its magnitude

$v_r = 662 / 539 = 1.23 m/s$

So the boat velocity vector relative to the bank is the sum of of the boat velocity vector relative to the water and the water velocity vector relative to the bank. Since these 2 component vectors are perpendicular to each other, the magnitude of the total vector can be calculated using Pythagorean formula:

$v = \sqrt{v_b^2 + v_r^2} = \sqrt{3^2 + 1.23^2} = \sqrt{9 + 1.5129} = \sqrt{10.5129} = 3.24$ m/s

5 0

3 years ago