How many moles is 1200 grams of Mn3(SO4)7?
2 answers:
no.of moles= mass/ Mr
=1200/(54.9*3)+7[32.1+(16*4)]
=1.433
1.64 moles
grams to mole
add all of them together 54.938+672.427=727.365
divide 1200/727.365=1.64979068
Just learned this in chemistry got a 100 on test.
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