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s344n2d4d5 [400]
4 years ago
6

Na-23 has 12 neutrons. What is it’s atomic number?

Chemistry
1 answer:
Dennis_Churaev [7]4 years ago
7 0

Answer:

11

Explanation:

The atomic number for Na will always be the same regardless of the number of neutrons.

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A column is packed with 0.5 g of a strongly acidic ion exchange resin in H+ form. A 1.0 M NaCl solution is passed through the co
Lena [83]

Answer:

The correct answer is 17 meq/g

Explanation:

Ion exchange capacity (IEC) express the total of active sites of a resin in which ions are attached because the greater molecular weight.

The exchange Reaction can be represented as

R-HR-H^{+} +  Na^{+} + Cl^{-} -> R-Na^{+} + HCl_{aq}

The IEC value (in meq/g) is determinated by using the next equation:

IEC=[(mL of NaOH)*(M of NaOH)]/mass of resin

IEC [(17 mL)*(0.5 M)/0.5]= 17 meq/g

3 0
4 years ago
An accelerating car is always gaining speed T or F
Sophie [7]
True because as a car accelerated it gains speed which propels it forward.
6 0
3 years ago
A compound consisting of atoms of large atomic mass is more likely to require:
UkoKoshka [18]
<span>A higher temperature to liquefy</span>
8 0
3 years ago
Read 2 more answers
To what temperature was 32.0L of gas at 2°C be heated for it to occupy 1.00*10^2L at the same pressure?
jolli1 [7]

Answer:

T₂ = 859.4 K

Explanation:

Given data:

Initial volume of gas = 32.0 L

Initial temperature = 2°C (2 + 273 = 275 k)

Final temperature = ?

Final volume = 1.00 ×10²L

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ /V₁  

T₂ = 1.00 ×10²L × 275 K / 32.0 L

T₂ = 27500 L.K / 32.0 L

T₂ = 859.4 K

8 0
4 years ago
The force of attraction between a divalent cation and a divalent anion is 1.64 x 10-8 N. If the ionic radius of the cation is 0.
Elden [556K]

The radius of the anion is 7.413 nm

<h3>How to calculate the force of attraction between charges</h3>

The force of attraction (F) is given by the formula:

  • F = (1/4π∈r²)(Zc*e)(Za*e)

where:

∈ = permittivity of free space = 8.85*10⁻¹⁵ F/m

Zc = charge on the cation = +2

Zc = charge on the anion = -2

e = charge on an electron = 1.602 * 10⁻¹⁹ C

r = interionic distance

r = rc + ra

where rc and ra are the radius of the cation and anion respectively

F = 1.64 * 10⁻⁸ N

Therefore based on the equation of force of attraction:

1.64 *10⁻⁸ = [1/4π(8.85*10⁻¹⁵)r²](2 * 1.602*10⁻¹⁹)²

r² = 5.63 * 10⁻¹⁷

r = 7.50 nm

Since r = rc + ra

where rc = 0.087 nm

thus, ra = r - rc = 7.50 - 0.087

ra = 7.413 nm

Therefore, the radius of the anion is 7.413 nm

Learn more about ionic radius at: brainly.com/question/2279609

6 0
3 years ago
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