Question

How much energy is transferred when 30.0 g of water is cooled from 25.0 °C to 12.7 °C.

Answer 1

Answer:

Heat transferred, Q = 1542.42 J

Explanation:

Given that,

Mass of water, m = 30 grams

Initial temperature, $T_i=25^{\circ} C$

Final temperature, $T_f=12.7^{\circ} C$

We need to find the energy transferred. The energy transferred is given by :

$Q=mc\Delta T$

c is specific heat of water, c = 4.18 J/g °C

So,

$Q=30\ g\times 4.18\ J/g-^{\circ} C\times (12.7-25)\ ^{\circ} C\\\\Q=-1542.42\ J$

So, 1542.42 J of energy is transferred.