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AURORKA [14]
3 years ago
13

What does electrical energy change to when you plug in an oven\

Physics
1 answer:
denpristay [2]3 years ago
3 0

-- If it's a toaster oven or the oven in an electric stove,
then it changes to thermal (heat) energy inside.

-- If it's a microwave oven, then it changes to light energy
when you open the door and the light goes on, also to
mechanical energy to turn the turntable, also to electromagnetic
(radio-wave) energy to do the cooking. 

Notice that the microwave oven does NOT use heat to do
the cooking.  It just shoots radio waves into the food, and
when the radio waves hit the water and fat molecules in
the food, those make the heat.  

You might be interested in
The odometer of a car changes from 1048 km to 1096 km in 40
Makovka662 [10]

Answer:

20m/s

Explanation:

it covers 20 metres in a second

3 0
2 years ago
In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.
BartSMP [9]

Answer:

The value of g in Kepler-12b is 3.85 m/s^{2}

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

W = m.g  (1)

Where m is the mass and g is the value of the gravity

F = G \frac{M.m}{R^{2}}  (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

m.g = G \frac{M.m}{R^{2}}  (3)

Then g will be isolated from equation 3:

g = G \frac{M.m}{m.R^{2}}

g = \frac{G.M}{R^{2}}  (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

d = 2R (5)

Where d and R are the diameter and radius of Jupiter

d_{jupiter} = 2(69911000 m)

d_{jupiter} = 139822000 m

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

d_{Kepler-12b} = 1.7(d_{jupiter})

d_{Kepler-12b} = 1.7(139822000 m)

d_{Kepler-12b} = 237697400 m

By means of equation 5 the radius of Kepler-12b can be known:

R_{Kepler-12b} = \frac{d}{2}

R_{Kepler-12b} = \frac{237697400 m}{2}

R_{Kepler-12b} = 118848700 m

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of 1.898x10^{27} kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

m_{Kepler-12b} = 0.43(m_{jupiter})

m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)

m_{Kepler-12b} = 8.161x10^{26} Kg

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}

g = 3.85 m/s^{2}

Hence, in Kepler-12b the gravity has a value of 3.85 m/s^{2}

8 0
3 years ago
this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the
Dafna1 [17]

The wavelength of the first harmonic of the standing wave is 2L.

<h3>What is a standing wave?</h3>

A standing wave is one in which the obvious points remain fixed as the vibration continues. A standing wave occurs in a wind instrument such as a trumpet, saxophone etc.

We know from  the formula of the first harmonic that the wavelength of the first harmonic of the standing wave is 2L.

Learn more about standing wave:brainly.com/question/1121886?

#SPJ11

3 0
2 years ago
Air enters a turbine operating at steady state at 8 bar, 1400 K and expands to 0.8 bar. The turbine is well insulated, and kinet
vladimir2022 [97]

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

T_1 =Temperature at inlet of turbine

T_2 = Temperature at exit of turbine

P_1 = Pressure at exit of turbine

P_2 =Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = m

m(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m_i = mass at inlet

m_0= Mass at outlet

h_i = Enthalpy at inlet

h_0 = Enthalpy at outlet

W = Work done

Q = Heat transferred

V_i = Velocity at inlet

V_0= Velocity at outlet

Z_i= Height at inlet

Z_0= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + W

W = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

\frac{T_2}{1400K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}

T_2 = 725.126K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

So:

W = h_i -h_0

W = C_p (T_1-T_2)

W = 1.005(1400-725.126)

W = 678.248kJ/Kg

Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg

5 0
4 years ago
When you rub two balloons on your sleeve, does it have positive or negative?
igomit [66]

When you rub the balloons, it will take electrons away, which is negative. So, the balloons are negative
6 0
3 years ago
Read 2 more answers
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