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IRISSAK [1]
3 years ago
6

If the gap between C and the rigid wall at D is initially 0.15 mm, determine the magnitudes of the support reactions at A and D

when the force P

Physics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer / Explanation

The question in the narrative is incomplete.

Kindly find the complete question below:

If the gap between C and the rigid wall at D is  initially 0.15 mm, determine the support reactions at A and  D when the force is applied. The assembly  is made of A36 steel

Procedure

Recalling the the equation of equilibrium and referencing the free body diagram of the assembly,

Therefore, ∑fₓ  = 0 ,

where, 20 ( 10³) - Fₐ - Fₙ = 0 --------------equation (1)

Now, recalling the compatibility equation, while utilizing the superposition method,

Therefore, δₓ - δfₓ

= 0.15  = 200(10³)(600) ÷ π/4 (0.05²)(200)(10⁹) - [ Fₐ (600) / π/4 (0.05²)(200)(10⁹) + Fₐ (600) π / 4 (0.05²)(200)(10⁹) ]

Solving this further,

We get: Fₐ = 20365.05 N

 Which is equivalent to = 20.4 kN.

Now, substituting the answer (Fₐ) into equation (1)

                Fₙ = 179634.95 N

                        = 180 kN

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nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

By putting the values

\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

μ g  =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

7 0
3 years ago
Read 2 more answers
How do I calculate the efficiency of motor
zepelin [54]

Answer:

the formula is efficiency = output / input × 100%

7 0
3 years ago
Please help on this one?
bezimeni [28]

Using the given equation you get:

E = 1.99x10^-25 / 9.0x10^-6

Divide 1.99 by 9.0: 1.99/9.0 = 0.22

For the scientific notation, when dividing subtract the two exponents:

25 -6 = 19

So you now have 0.22 x 10^-19

Now you need to change the 0.22 to be in scientific notation form:

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The answer is B.

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2 years ago
The FM radio band in most places goes from frequencies of about 89 MHz to 106 MHz. How long is the wavelength of the radiation a
ohaa [14]

Answer:

2.83 m

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is given by

\lambda=\frac{c}{f}

where

\lambda is the wavelength

c=3.0\cdot 10^8 m/s is the speed of light

f is the frequency

For the FM radio waves in this problem, we have:

f_1=89 MHz=89\cdot 10^6 Hz is the minimum frequency, so the maximum wavelength is

\lambda_2=\frac{c}{f_1}=\frac{3\cdot 10^8}{89\cdot 10^6}=3.37 m

The maximum frequency is instead

f_2=106 MHz=106\cdot 10^6 Hz

Therefore, the minimum wavelength is

\lambda_1=\frac{c}{f_2}=\frac{3\cdot 10^8}{106\cdot 10^6}=2.83 m

So, the wavelength at the beginning of the range is 2.83 m.

8 0
2 years ago
A man walks 7 km, east in 2 hours and 2 km in 1 hour in the same direction. a) what is
Rzqust [24]

Explanation:

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|v| = 3 km/hr

Average velocity = displacement / time

v = (7 km east + 2 km east) / (2 hr + 1 hr)

v = 3 km/hr east

8 0
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