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Tom [10]
3 years ago
12

20. A 0.145 kg mass of tungsten at 130.0 °C is placed in a 0.502 kg of water at 22.0 °C. The mixture reaches equilibrium at 28.6

°C. Calculate the specific heat of tungsten. (specific heat of water = 4180 J/kg C)
Givens:


Unknown:


Equation: macaΔTa = - mbcbΔTb


Substitute:


Solve:
Physics
1 answer:
zepelin [54]3 years ago
8 0
MaCa∆Tb = MbC∆Tb
Where m is the mass of a compound
<span> C is the specific heat of a compound 
</span>∆T is the change of temperature of the compound  
<span> (0.502 kg water)(4180 j/kg C)( 28.6 – 22 C) = ( 0.145 kg tungsten) ( C ) ( 130 – 28.6 C) 
</span>Solve for C
<span>C = 941.9 J /kg C </span>
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