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3 years ago

A rock is dropped from rest. How fast is it going after it has been falling for 9.2 s?

Physics

1 answer:

natka813 [3]3 years ago

6 0

90.2 m/s. A rock dropped from rest after it has falling for 9.2 seconds will have a velocity of 90.2m/s.

The bodies left in free fall increase their speed (downwards) by 9.8 m/s² every second. The acceleration of gravity is the same for all objects and is independent of the masses of these. In the free fall the air resistance is not taken into account.

v = g*t

v = (9.8m/s²)(9.2s) = 90.2 m/s

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3 years ago

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3 years ago

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dalvyx [7]

The relationship between variables might be either directly porportional to each other or inversely proportional to each other. <em>For instance, the current flowing is _</em><em><u>directly</u></em><em>_ </em><em>proportional to the potential difference across</em> it.

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Since I do not have the graph, I will propose two potential options and I will describe each of them.

I suggest you to choose the one that matches the shape of graph 3.

<h3>Graphs</h3>

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<h3 /><h3 /><h3>Option 2 </h3>

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In the attached files you will find graphs of both options.

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You can learn more about the Ohm's law at

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