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Monica [59]
4 years ago
14

A rock is dropped from rest. How fast is it going after it has been falling for 9.2 s?

Physics
1 answer:
natka813 [3]4 years ago
6 0

90.2 m/s. A rock dropped from rest after it has falling for 9.2 seconds will have a velocity of 90.2m/s.

The bodies left in free fall increase their speed (downwards) by 9.8 m/s² every second. The acceleration of gravity is the same for all objects and is independent of the masses of these. In the free fall the air resistance is not taken into account.

v = g*t

v = (9.8m/s²)(9.2s) = 90.2 m/s

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Canada’s northern territories experience "midnight sun," meaning what?.
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Answer:

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6 0
3 years ago
How does inertia affect someone who isn't wearing a seatbelt
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7 0
4 years ago
A 2MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T.the force on a proton is
Snowcat [4.5K]

Answer:

7.8x10-12N

Explanation:

We know that

Magnetic force = F = qVB

And

Also Kinetic energy K.E is

E = (1/2)mV²

So making v subject

V = √(2E / m)

And

E = KE = 2MeV

= 2 × 106 eV

= 2 × 106 × 1.6 × 10–19 J

= 3.2 × 10–13 J

And then

V= √2x3.2E-13/1.6E-27

1.9E7m/s

Given that

mass of proton = 1.6 × 10–27 kg,

Magnetic field strength B = 2.5 T.

So F= qBv sinစ

=

So F = 1.6 × 10–19 × 2.5 × 1.9 x10^7 x sin 90°

= 7.8 x 10^-12N

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3 years ago
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Its D.

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3 years ago
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Becsud it's not moving
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