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4 years ago

What’s the answer anyone??

Physics

2 answers:

lozanna [386]4 years ago

8 0

The answer according to me is 5,200, 3,750, and 0.5 .

saul85 [17]4 years ago

5 0

Answer:

5.2L == 5200 mL

3.75 kg == 3750 g

500 mm == 0.5 m

Explanation:

For liters to milliliters, simply multiply by 1000.

For kilograms to grams, simply multiply by 1000

For millimeters to meters, simply divide by 1000.

Cheers.

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The driver of a stationary car hears a siren of an approaching police car at a frequency of 280Hz. If the actual frequency of th

deff fn [24]

Answer:

The speed of the police car is 294 m/s

Explanation:

Given;

frequency of the siren in air, f = 280 Hz

speed of sound in air, v = 343 m/s

Determine the wavelength of the sound in air to the stationary car:

v = fλ

where;

λ is wavelength of the sound

λ = v/f

λ = 343 / 280

λ = 1.225 m

Now, determine the speed at which the police car is approaching the stationary car;

The actual frequency of the police car, F = 240 Hz

V = Fλ

Where;

V is speed of the police car

λ is the distance between the police car and the stationary car, (wavelength)

V = 240 x 1.225

V = 294 m/s

Therefore, the speed of the police car is 294 m/s

5 0

3 years ago

What speed should a satellite with a mass of 1500 kg at 8,500 km above the center of the earth be traveling at in order to stay

hodyreva [135]

Answer:

6844.5 m/s.

Explanation:

To get the speed of the satellite, the centripetal force on it must be enough to change its direction. This therefore means that the centripetal force must be equal to the gravitational force.

Formula for centripetal force is;

F_c = mv²/r

Formula for gravitational force is:

F_g = GmM/r²

Thus;

mv²/r = GmM/r²

m is the mass of the satellite and M is mass of the earth.

Making v the subject, we have;

v = √(GM/r)

We are given;

G = 6.67 × 10^(-11) m/kg²

M = 5.97 × 10^(24) kg

r = 8500 km = 8500000

Thus;

v = √((6.67 × 10^(-11) × (5.97 × 10^(24)) /8500000) = 6844.5 m/s.

7 0

3 years ago

Read 2 more answers

For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.

NeX [460]

(1) The critical angles for the fused quartz is 44⁰,

(2) The critical angles for the polystyrene is 39⁰.

(3) The critical angles for the sodium chloride is 41⁰.

<h3>What is Critical angles?</h3>

In optics, the critical angle is the topmost angle at which a shaft of light traveling in one transparent medium can strike the boundary between that medium and another with a lower refractive indicator without being fully reflected within the first

Critical angles for the different medium.

θ $=sin^{-1}\frac{n_{2} }{n_{1} }$

where;

$n_{2}$ is the refractive index of air = 1

$n_{1}$ is the refractive index of the given substances.

Refractive index of quartz glass = 1.46

Refractive index of polystyrene = 1.59

Refractive index of sodium chloride = 1.54

Critical angles for quartz glass:

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.46}\\$

$\theta_{\text {crit }}=44^{o}$

Critical angles for polystyrene

$$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.59}\\\\$

$\theta_{\text {crit }}=39^{\circ}$

Critical angles for Sodium Chloride

$$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.54}\\$

$\theta_{\text {crit }}=41^{o}$

Thus, the critical angles for the quartz glass is 44⁰, the critical angles for the polystyrene is 39 ⁰ and the critical angles for the sodium chloride is 41⁰.

To know more about critical angle visit:
brainly.com/question/3314727

#SPJ4

I understand that the question you are looking for is:

"For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.

(a) Fused Quartz

(b) Polystyrene

8 0

2 years ago

g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin

Ymorist [56]

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

$i.e Normal \ Force(N) = mg cos \theta$

And $\theta = 90$ so

$N = 0$

An example will be a where a stone is attached to the end of a string and is made to move in a circular motion while keeping the other end of the string in a fixed position

A dog walking along a surface which has friction, here the frictional force would acting in the direction of the motion and this would do positive work

Explanation:

5 0

3 years ago

Read 2 more answers

An object accelerates downward at a constant rate of 2.00 m/s2 while completely submerged in water. Neglect the viscosity (fluid

Sidana [21]

Answer:

833kg/m³

Explanation:

We have volume as Vm³

Density of this object = dKg/m³

Water density = 1000kg/m³

g = 10m/s²

We calculate FB which is the the buoyant force on object. Calculated as volume of object multiplied by water density

Fb = 1000Vg upwards

W = Vdg

Acceleration = net upwards/m

M = mass

2 = (1000g-gd)/d

2d = 10000 - 10d

2d + 10d = 10000

12d = 10000

d = 833.33kg/m³

Approximately 833kg/m³

The average density of the object is therefore 833kg/m³

5 0

3 years ago