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docker41 [41]
3 years ago
13

When sighting a firearm using an open sight, in what direction should the rear sight be moved if you want the shot to travel to

the right
Physics
1 answer:
sattari [20]3 years ago
3 0

Explanation:

Test to see where the bullets gather on your target after shooting a number of shots. Change the targets of your weapon if the bullets are not in the target's middle. Try to shift the rear view in the same direction with an open sight that you would like to push the shots on the target.

After the rifle is sighted-in, one must practice firing under various lighting and weather conditions, and at different distances to be able to become accurate and proficient shooter.

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a 200 kg block is lifted at a constant speed of 0.5 m/s by a steel cable that passes over a massless, frictionless pulley to a m
Tresset [83]

Questions

(a) What is the magnitude of the force exerted by the cable?

(b) What is the magnitude of the torque exerted by the cable on the winch drum?

(c) What is the angular velocity of the winch drum?

(d) What power must be developed by the motor to drive the winch drum?

Answer:

(a) 1962 N

(b) 588.6 N.m

(c) 1.67 rads/s

(d) 982.962 W

Explanation:

(a)

Force, F=mg where m is the mass of the block and g is acceleration due to gravity. Taking the value of acceleration due to gravity as 9.81 m/s2 and substituting 200 Kg for mass then the force exerted on the cable will be

F=200*9.81=1962 N

(b)

Torque is a product of force and distance. Since the force is already derived in part (a) above and the radius is given as 30 cm converted to m we have 0.3 m then torque, T= 1962*0.3=588.6 N.m

(c)

Angular velocity= \frac {v}{r} where v is the speed of block and r is the radius of the wheel. Substituting 0.5 m/s for v and 0.3 m for r then the angular velocity will be \frac {0.5}{0.3}=1.6667\approx 1.67 rads/s

(d)

Power, P is a product of torque and angular velocity and since torque is already given in part b above as 588.6 N and the angular velocity in part c then power, P= 588.6*1.67=982.962 W

3 0
4 years ago
1. How much force would you have to apply to a 15kg object in order to accelerate it!<br> a 2 m/s?
mihalych1998 [28]

30N

Explanation:

Given parameters:

Mass of object = 15kg

Acceleration = 2m/s

Unknown:

Force = ?

Solution:

Force is given as the product of mass and acceleration:

         F = m x a

   m is the mass

    a is the acceleration

Inputting the parameters:

     F = 15 x 2 = 30N

The unit of force is newtons, N .

Learn more:

Force brainly.com/question/10470406

#learnwithBrainly

3 0
3 years ago
You are traveling at 55 mi/h along the x-axis relative to a straight, level road and pass a car that is traveling at 45 mi/h. Th
Alik [6]

Answer:

10 mph

Explanation:

55 - 45 = 10 mph

4 0
2 years ago
There is a limit to how long your neck can be. If your neck were too long, no blood would reach your brain! What is the maximum
spayn [35]

Answer:

The maximum height a person's brain could be above his heart is: 1.28 meter.

Explanation:

We need to know what is the normal blood pressure ours hearts so there is a rate: 120/80 (mmHg) and the average will be: 100 (mmHg) and using the Pascal law that relate pressure, density, gravity and height like:P_{2} = pgh_{1} - pgh_{2} + P_{1}, where P is pressure, p is density, g is the gravity acceleration and h is the height. Now we can find the height and delta of pressure will be: P2-P1 = 100 (mmHg), knowing that 1(mmHg) is equal to 133 Pa, we can do the convertion to 13332.2 (Pa), now because the units of Pascal are Newton/(meter^2). Then we solve the formula to get the height: \frac{P2-P1}{pg} =h so we get:\frac{13332.2}{(1060*9,81)}=Height=1.28(meters).

5 0
3 years ago
In 1993, Cuban athlete Javier Sotomayor set the world record for the high jump. The gravitational potential energy associated wi
Katarina [22]

Answer:2.541

Explanation:

Well , Potential Energy = mgh

m=mass = 82

g=acceleration of gravity=9.80m/s^2

h=what we are looking for

PE=mgh

PE/(mg) = h

Substitute in the values:

1970/(82 x 9.8) = h 2.541

5 0
4 years ago
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