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docker41 [41]
3 years ago
13

When sighting a firearm using an open sight, in what direction should the rear sight be moved if you want the shot to travel to

the right
Physics
1 answer:
sattari [20]3 years ago
3 0

Explanation:

Test to see where the bullets gather on your target after shooting a number of shots. Change the targets of your weapon if the bullets are not in the target's middle. Try to shift the rear view in the same direction with an open sight that you would like to push the shots on the target.

After the rifle is sighted-in, one must practice firing under various lighting and weather conditions, and at different distances to be able to become accurate and proficient shooter.

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A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0
3 years ago
Kinetic friction is affected by the weight of the object. True or false?
nevsk [136]

True Kinetic friction is affected by the weight of the object

3 0
3 years ago
How does an executive order differ from a statue?
ICE Princess25 [194]

Answer: Executive Order on Protecting American Monuments, Memorials, and Statues against our country are public monuments, memorials, and statues.

Explanation: learned it last week

6 0
2 years ago
Long ding dong what it do?
Andre45 [30]

Answer:

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Explanation:

3 0
3 years ago
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A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−
Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m.

Explanation:

Given that,

The actual wavelength of the hydrogen atom, \lambda_a=5.13\times 10^{-7}\ m

A hydrogen atom in a galaxy moving with a speed of, v=6.65\times 10^6\ m/s

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}

\lambda_o is the observed wavelength

\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m

So, the observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m. Hence, this is the required solution.

8 0
2 years ago
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