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Lyrx [107]
4 years ago
10

Which of the following statements is true about magnetic fields. Magnets and magnetic fields were only just discovered in the la

st 500 years. The earth’s magnetic field is confined within the core of the earth. The earth’s magnetic field protects the surface from strong electrical currents coming from the sun. Magnetic fields are unreliable for use in navigation.
Physics
2 answers:
garik1379 [7]4 years ago
8 0

Answer:

Pushing magma up through the interior of earth

Explanation:

MrRissso [65]4 years ago
7 0

Answer:

is D

Explanation:

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4 years ago
A beam of microwaves with λ = 0.9 mm is incident upon a 9 cm slit. At a distance of 1.5 m from the slit, what is the approximate
liq [111]

Answer:

3 cm

Explanation:

According to the question,

D=1.5 m.

d=9 cm.

\lambda =0.9 mm.

Now the approximate slit's image width is equal to width of central maxima.

And width of central maxima is twice the width from center to first maxima

So,

y=2\frac{\lambda (D)}{d}.

Substitute all the variable in above equation.

y=\frac{(2)0.9\times 10^{-2} m(1.5 m) }{0.09 m}.

y=3 cm.

5 0
3 years ago
PLEASE HELP WILL GIVE BRANLIEST IF CORRECT
coldgirl [10]

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3 0
3 years ago
Read 2 more answers
What kind of weather would MOST LIKELY lead to hurricane formation?
krok68 [10]

Answer:

The recipe for a hurricane is a combination of warm, humid wind over tropical waters. The temperature of tropical waters must be at least 80 degrees F for up to 165 feet below the ocean’s surface. As this warm water meets the wind that blows west from Africa across the ocean, it causes the water to vaporize. The water vapor then rises into the atmosphere, where it cools and liquefies.

Explanation:

I hope this helps

7 0
3 years ago
Please help on this one
Sphinxa [80]

Since this is a projectile motion problem, break down each of the five kinematic quantities into x and y components. To find the range, we need to identify the x component of the displacement of the ball.

Let's break them down into components.

                X                                Y

v₁     32 cos50 m/s           32 sin50 m/s

v₂     32 cos50 m/s                    ?

Δd             ?                                0

Δt              ?                                ?

a                0                         -9.8 m/s²


Let's use the following equation of uniform motion for the Y components to solve for time, which we can then use for the X components to find the range.

                           Δdy = v₁yΔt + 0.5ay(Δt)²

                                0 = v₁yΔt + 0.5ay(Δt)²

                                0 = Δt(v₁ + 0.5ayΔt), Δt ≠ 0

                                0 = v₁ + 0.5ayΔt

                                0 = 32sin50m/s + 0.5(-9.8m/s²)Δt

                                0 = 2<u>4</u>.513 m/s - 4.9m/s²Δt

                 -2<u>4</u>.513m/s = -4.9m/s²Δt

-2<u>4</u>.513m/s  ÷ 4.9m/s² = Δt

                          <u>5</u>.00s = Δt


Now lets put our known values into the same kinematic equation, but this time for the x components to solve for range.

Δdₓ = v₁ₓΔt + 0.5(a)(Δt)²

Δdₓ = 32cos50m/s(<u>5</u>.00s) + 0.5(0)(<u>5</u>.00)²

Δdₓ = 32cos50m/s(<u>5</u>.00s)

Δdₓ = 10<u>2</u>.846


Therefore, the answer is A, 102.9m. According to significant digit rules, neither would be correct, but 103m is the closest to 102.9m so I guess that is what it is.






6 0
3 years ago
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