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goldfiish [28.3K]
3 years ago
14

In testing the effectiveness of an antacid compound, 20.0g of Hydrochloric Acid is mixed with 28.0g of Magnesium Hydroxide. Will

the base neutralize (Completely use up) all of the acid? How much of which substance is in excess? 2HCL + (OH)2 -> MgCl2 + 2H20
Chemistry
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

Base Mg(OH)2 does neutralise the acid and is 12g in excess.

Explanation:

2HCL +Mg(OH)2 -> MgCl2 + 2H20

2 * 36.458 g of HCL react with  58.319 g of  Mg(OH)2 to neutralise it.

72.916 HCl reacts with  58.319 g of the base.

So 20 g HCl reacts with  (58.319/72.916) * 20 = 16g.

There are 28 g of Mg(OH)2 so the base does neutralise all the acid.

The Mg(OH)2 is 28 - 16 = 12 g in excess.

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Vesna [10]
The emperical formula for benzene (C6H6) is “CH”.
7 0
3 years ago
How many moles of solute are contained in a 250.0-milliliter solution that has a concentration of 0.85 M?
adoni [48]

Answer : The correct option is, 0.21 moles

Solution : Given,

Molarity of the solution = 0.85 M = 0.85 mole/L

Volume of solution = 250 ml = 0.25 L     (1L=1000ml)

Molarity : It is defined as the number of moles of solute present in one liter of the solution.

Formula used :

Molarity=\frac{\text{moles of solute}}{\text{Volume of solution in liters}}

Now put all the given values in this formula, we get the moles of solute of the solution.

0.85mole/L=\frac{\text{moles of solute}}{0.25L}

\text{moles of solute}=0.2125=0.21moles

Therefore, the moles of solute is, 0.21 moles

7 0
3 years ago
Read 2 more answers
Summarize Hooke's observations of cork under the microscope
ratelena [41]

Answer:

I don't know

Explanation:

pls I need a little bit answer

7 0
2 years ago
What is the molarity of a solution in which 250 grams of NaCl are dissolved in 2.9 L of water?
Maksim231197 [3]

Answer:

About 1.48 M.

Explanation:

The formula for molarity is mol/L.

So firstly, you must find the amount of moles in 250 grams of NaCl.

I do this by using stoichiometry. First, I find how nany grams are in a single mole of NaCl. This is around 58.44 grams/mole. Now that I know this, I can now use a stoich table. (250 g NaCl * 1 mol NaCl / 58.44 g NaCl). I plug this into my calculator.

I get that 250 grams of NaCl is equal to about 4.28 moles.

Now I just plug into the formula!

4.28 moles/2.9 L = about 1.48

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3 0
1 year ago
4. How many grams are in 54 moles H,O?
Marrrta [24]

Answer:

Explanation:1.8

×

10

24

 water molecules.

Explanation:

There are  

6.022

×

10

23

molecules in a mole.

There are  

18.01528

grams of water per mole of water.

These can be figured out using the concept of moles and molecular weight. I have attached a video that provides a good explanation.

Explanation of moles and molecular weight

Now you have all the information needed to solve the problem.

You start out with 54 grams of water. You want to convert that into molecules, but how can you do that? You can't go directly from grams to molecules because there is no easy unit conversion. However, you can go from grams to moles using

18.01528

grams of water per mole of water.

From there, you can go from moles to molecules using  

6.022

×

10

23

molecules in a mole.

A T chart is useful for this kind of problem.

54 g H

2

O

×

1 mol  H

2

O

18.0152 g H

2

O

×

6.022

×

10

23

 

molecules

1 mol H

2

O

54

g H

2

O

×

1 mol  H

2

O

18.0152

g H

2

O

×

6.022

×

10

23

 

molecules

1 mol H

2

O

Notice when you apply this T chart, the units cancel out, leaving molecules in the final answer, which is the correct units.

Now actually multiply everything out

54

×

6.022

×

10

23

18.0152

=

1.805

×

10

24

You are left with  

1.8

×

10

24

water molecules (rounded to two sig figs).

8 0
3 years ago
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