The emperical formula for benzene (C6H6) is “CH”.
Answer : The correct option is, 0.21 moles
Solution : Given,
Molarity of the solution = 0.85 M = 0.85 mole/L
Volume of solution = 250 ml = 0.25 L 
Molarity : It is defined as the number of moles of solute present in one liter of the solution.
Formula used :

Now put all the given values in this formula, we get the moles of solute of the solution.


Therefore, the moles of solute is, 0.21 moles
Answer:
I don't know
Explanation:
pls I need a little bit answer
Answer:
About 1.48 M.
Explanation:
The formula for molarity is mol/L.
So firstly, you must find the amount of moles in 250 grams of NaCl.
I do this by using stoichiometry. First, I find how nany grams are in a single mole of NaCl. This is around 58.44 grams/mole. Now that I know this, I can now use a stoich table. (250 g NaCl * 1 mol NaCl / 58.44 g NaCl). I plug this into my calculator.
I get that 250 grams of NaCl is equal to about 4.28 moles.
Now I just plug into the formula!
4.28 moles/2.9 L = about 1.48
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Answer:
Explanation:1.8
×
10
24
water molecules.
Explanation:
There are
6.022
×
10
23
molecules in a mole.
There are
18.01528
grams of water per mole of water.
These can be figured out using the concept of moles and molecular weight. I have attached a video that provides a good explanation.
Explanation of moles and molecular weight
Now you have all the information needed to solve the problem.
You start out with 54 grams of water. You want to convert that into molecules, but how can you do that? You can't go directly from grams to molecules because there is no easy unit conversion. However, you can go from grams to moles using
18.01528
grams of water per mole of water.
From there, you can go from moles to molecules using
6.022
×
10
23
molecules in a mole.
A T chart is useful for this kind of problem.
54 g H
2
O
×
1 mol H
2
O
18.0152 g H
2
O
×
6.022
×
10
23
molecules
1 mol H
2
O
54
g H
2
O
×
1 mol H
2
O
18.0152
g H
2
O
×
6.022
×
10
23
molecules
1 mol H
2
O
Notice when you apply this T chart, the units cancel out, leaving molecules in the final answer, which is the correct units.
Now actually multiply everything out
54
×
6.022
×
10
23
18.0152
=
1.805
×
10
24
You are left with
1.8
×
10
24
water molecules (rounded to two sig figs).