All categories

3 years ago

What element is necessary for a healthy eye

Chemistry

1 answer:

Salsk061 [2.6K]3 years ago

3 0

The element necissary for an eye is plain vision, oxygen,

You might be interested in

I need help yall ill mark brainliest :)

garri49 [273]

Answer:

How does non-human life in an urban ecosystem differ from that in an undeveloped forest ecosystem?

Explanation:

In forest eco system the people are uncivilized and not so much educated. And in urban eco system people are intelligent as well as educated this is the main reason. In an urban ecosystem, the only non-human life that live there are the ones that are able to survive under the conditions. However, in undeveloped forest ecosystems, there’s barely any pollution. Therefore, a bigger variety of non-human life is able to live here.

Mark brainliest if you can please :)

3 0

3 years ago

A chemist has one solution that is 80% acid and another solution that is 30% acid. how much of the second (30%) solution is need

Aleksandr [31]

messed up oops !!!!!!!!!

8 0

3 years ago

How many liters of oxygen are in 8.32 moles of oxygen at STP

Jlenok [28]

Answer:

186 Liters at STP conditions

Explanation:

1 mole of any gas at STP conditions occupies 22.4 Liters.

Therefore, 8.32 moles O₂(g) = 8.32 moles x 22.4Liters/mole = 186 Liters (3 sig.figs.)

6 0

3 years ago

How is the electron cloud model different from Bohr's atomic model?

Cerrena [4.2K]

In the electron cloud model, the atoms are in unpredicted places. But in the Bohr model, atoms are in "rows"

7 0

4 years ago

An analytical chemist is titrating of a solution of ethylamine with a solution of . The of ethylamine is . Calculate the pH of t

Elenna [48]

Answer:

pH=11.

Explanation:

Hello!

In this case, since the data is not given, it is possible to use a similar problem like:

"An analytical chemist is titrating 185.0 mL of a 0.7500 M solution of ethylamine(C2HNH2) with a 0.4800 M solution of HNO3.ThepK,of ethylamine is 3.19. Calculate the pH of the base solution after the chemist has added 114.4 mL of the HNO3 solution to it"

Thus, for the reaction:

$C_2H_5NH_2+H^+\rightleftharpoons C_2H_5NH_4^+$

Tt is possible to compute the remaining moles of ethylamine via the following subtraction:

$n_{ethylamine}=0.1850L*0.7500mol/L=0.1365mol\\\\n_{acid}=0.1144L*0.4800mol/L=0.0549mol\\\\n_{ethylamine}^{remaining}=0.1365mol-0.0549mol=0.0816mol$

Thus, the concentration of ethylamine in solution is:

$[ethylamine]=\frac{0.0816mol}{0.1850L+0.1144L}=0.2725M$

Now, we can also infer that some salt is formed, and has the following concentration:

$[salt]=\frac{0.0549mol}{0.1850L+0.1144L}=0.1834M$

Therefore, we can use the Henderson-Hasselbach equation to compute the resulting pOH first:

$pOH=pKb+log(\frac{[salt]}{[base]} )\\\\pOH=3.19+log(\frac{0.1834M}{0.2725M})\\\\pOH=3.0$

Finally, the pH turns out to be:

$pH=14-pOH=14-3\\\\pH=11$

NOTE: keep in mind that if you have different values, you can just change them and follow the very same process here.

Best regards!

4 0

3 years ago