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stepladder [879]
3 years ago
5

What is the pressure exerted by 1.2 moles of a gas with a

Chemistry
2 answers:
eduard3 years ago
8 0
The answer is b 1.0atm in mathematics always avoid going thru the loop hole just focus at the problem
olga2289 [7]3 years ago
5 0

Answer:3.0 atm

Use idealgas law. PV=nRT

Plug in your numbers. Temp in Kelvin. Explanation:

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Review this balanced neutralization reaction: HBr + KOH KBr + H2O. Which substance is the base?
Olegator [25]
B KOH
I would say this is the base for the compound substance
8 0
3 years ago
The Groups 1 and 2 on the periodic table contain what atom type?
Bumek [7]
Non metals
and metals
8 0
3 years ago
Read 2 more answers
Americans combined drive about 4.0 x 109 kilometers a day and get an average of 20 miles per gallon of gasoline. For each kilogr
Nimfa-mama [501]

Answer:

303,882.84649 kg\times 3=9.12\times 10^5 kg of carbon dioxide gas.

Explanation:

Average distance covered by Americans in a day= 4.0\times 10^9 km

1 day = 24 × 60 min = 1,440 min

Average distance covered by Americans in a minute= \frac{4.0\times 10^9 km}{1,440}=2,777,777.78 km

Average mileage of the car = 20 miles/gal = 32.18 km/gal

1 mile = 1.609 km

20 miles = 20 × 1.609 km = 32.18 km

Volume of gasoline used in minute = \frac{2,777,777.78 km}{32.18 km/gal}

V=86,320.00 gal

V=86,320.00\times 3.7854 L

(1 L = 1000 mL)

V=86,320.00\times 3.7854 \times 1000 mL=326,755,748.91 mL

Mass of 86,320.00 gallons of gasoline = m

Density of the gasoline = d = 0.93 g/cm^3=0.93 g/mL

1 mL= 1 cm^3

m=d\times V=0.93 g/mL\times 326,755,748.91 mL

m=303,882,846.49 g=303,882.84649 kg

1 kilogram of gasoline gives 3 kg of carbon dioxde gas .

Then 303,882.84649 kg of gasoline will give :

303,882.84649 kg\times 3=9.12\times 10^5 kg of carbon dioxide gas.

8 0
3 years ago
Q Q 3. (08.02 MC)
AnnyKZ [126]

Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Explanation:

Given: V_{1} = ?,         M_{1} = 0.55 M

V_{2} = 100.0 mL,        M_{2} = 2.50 M

Formula used to calculate the volume of KBr is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.55 M \times V_{1} = 2.50 M \times 100.0 mL\\V_{1} = 455 mL

Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

7 0
3 years ago
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Why should an acid be handled with caution​
tiny-mole [99]

Explanation:

acid should be handled with caution because it is dangerous as it may burn the skin

7 0
2 years ago
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