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stepladder [879]
3 years ago
5

What is the pressure exerted by 1.2 moles of a gas with a

Chemistry
2 answers:
eduard3 years ago
8 0
The answer is b 1.0atm in mathematics always avoid going thru the loop hole just focus at the problem
olga2289 [7]3 years ago
5 0

Answer:3.0 atm

Use idealgas law. PV=nRT

Plug in your numbers. Temp in Kelvin. Explanation:

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drek231 [11]

Answer:

Light demonstrates wave-like and particle-like characteristics

Explanation:

Light itself is a wave but under circumstance it will present particle-like charcteristics. This is called wave-particle duality :)

5 0
2 years ago
Pure acetic acid (hc2h3o2) is a liquid and is known as glacial acetic acid. calculate the molarity of a solution prepared by dis
Alexandra [31]
In order to find the molarity of the solution, we first require the moles of acetic acid added. For this,we need the mass which is:

Mass = volume * density

Mass = 50 * 1.05
Mass = 52.5 grams


Moles = mass / molecular weight

Moles = 52.5 / 60.05 
Moles = 0.874 mol

Next, we know that the molarity of a solution is:

Molarity = moles / liter
Molarity = 0.874 / 0.5

Molarity = 1.75 M
3 0
2 years ago
Read 2 more answers
What is the molecular weight of bromoform if 2.50X10^-2 mol weighs 6.33 g
babymother [125]
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8 0
3 years ago
What is chemical energy?
-Dominant- [34]
Answer:
I think it’s D
Explanation:
Chemical strength, Chemical compounds have energy contained in their bonds. Chemical energy may be emitted in the form of heat during a chemical reaction, which is known as an exothermic reaction. The body transforms the chemical energy in food into mechanical energy and heat.
8 0
3 years ago
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
2 years ago
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