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baherus [9]
3 years ago
12

determine the equation of the line that has the given slope and travels through thegiven point (3,-4) and m=2

Mathematics
1 answer:
iren2701 [21]3 years ago
6 0
Y = mx + c
-4 = 2(3) + c
-4 = 6 + c
-10 = c

y = mx + c
y = 2x - 10
Hence, the equation is y=2x-10.
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Find the equation of the line in slope-intercept form (-1,-1) and (1,0)
ArbitrLikvidat [17]

Answer:

An equation in slope-intercept form of the line will be

  • y\:=\frac{1}{2}x-\frac{1}{2}

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept

Given the points

  • (-1, -1)
  • (1, 0)

Finding the slope between (-1,-1) and (1,0)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-1,\:-1\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)

m=\frac{0-\left(-1\right)}{1-\left(-1\right)}

m=\frac{1}{2}

substituting m = 1/2 and (-1, -1) in the slope-intercept form of the line equation to determine the y-intercept

y = mx+b

-1=\frac{1}{2}\left(-1\right)+b

-\frac{1}{2}+b=-1

Add 1/2 to both sides

-\frac{1}{2}+b+\frac{1}{2}=-1+\frac{1}{2}

b=-\frac{1}{2}

substituting m = 1/2 and b = -1/2 in the slope-intercept form of the line equation

y = mx+b

y\:=\frac{1}{2}x+\left(-\frac{1}{2}\right)

y\:=\frac{1}{2}x-\frac{1}{2}

Therefore, an equation in slope-intercept form of the line will be

  • y\:=\frac{1}{2}x-\frac{1}{2}
3 0
2 years ago
HELP PLEASE IM REALLY STUCK
liberstina [14]
The 15th term will be 71. Why? Well, see below for an explanation!

By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:

First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
Ninth term: 41
Tenth term: 46
Eleventh term: 51
Twelfth term: 56
Thirteenth term: 61
Fourteenth term: 66
Fifteenth term: 71

By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.

Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
4 0
2 years ago
What is the sum of 56+64 writen as the product of its gcf and another sum
jenyasd209 [6]
<span>Look for the sum of 56 and 64, written as the product of its GCF and another sum.
First, let’s find the greatest common factor of both given numbers:
=> 56 = 1, 2, 4, 7, 8, 13, 28 and 56
=> 64 = 1, 2, 4, 8, 16, 32, and 64
Now, we need to find the greatest common factor between the two numbers. The GCF of the 2 numbers is 8.
=> 56 / 8 = 7
=> 64 / 8 = 8
=> 56 + 64 = 120
=> (8 x 7) + (8 x 8)
=> 56 + 64
=> 120.</span><span>

</span>



3 0
3 years ago
Quincy was stuck inside during an afternoon rainstorm. He spent 20 minutes reading books, 18 minutes eating lunch, 12 minutes wa
Scorpion4ik [409]

Answer:

the hell you are talking about?

Step-by-step explanation:

6 0
3 years ago
The average a of two numbers c and d is equal to half the sum of c and d.
monitta

Answer:

\frac{c + d}{2} =  \frac{c + d}{2}

5 0
3 years ago
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