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Mama L [17]
2 years ago
14

Which of the following substance is being reduced in the following reaction.? Cu (s) + 2AgNO3 (aq) + 2Ag (s) + Cu(NO3)2 (aq) A)

AgNO3 B) Cu C) Ag D) Cu(NO3)2
Chemistry
1 answer:
nikklg [1K]2 years ago
3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)

The half reactions for the above reaction are:

Oxidation half reaction: Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-

Reduction half reaction:  2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)

From the above reactions, copper is loosing its electrons. Thus, it is getting oxidized.

Silver ion is gaining electrons and thus is getting reduced.

Hence, the correct answer is Option A.

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3 years ago
Hno3, a strong acid, is added to shift the ag2co3 equilibrium (equation 7.6) to the right. explain why the shift occurs.
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Answer 1)  When a strong acid like HNO_{3} reacts with Ag_{2} CO_{3} usually the equilibrium shifts to the right because

As per the Le chatelier's principle "if in any reaction, a dynamic equilibrium is disturbed by changing the any of the conditions, the position of equilibrium moves to counteract the change."  So, in the given reaction when HNO_{3} reacts with Ag_{2} CO_{3}  it generates carbon dioxide and water as a by product, if we are adding HNO_{3} it will remove some of the CO_{3} molecule from the reaction mixture, which then tends to shift the equilibrium towards right.

Answer 2) The same would be observed in this case, if we replace HNO_{3} with HCl it will shift the equilibrium to the right as their will be generation of AgCl as the precipitate.

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