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Mars2501 [29]
4 years ago
11

Why are mercury thermometers rarely used in the laboratory?

Chemistry
2 answers:
ozzi4 years ago
8 0
Because it is one of the strongest chemicals and it is very dangerous.
defon4 years ago
6 0
They are rarely used because they pose a danger hazard when they are broken. Mercury is highly toxic
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HELP I DON'T HAVE MUCH TIME PLZ HELP ME IF YOU ARE REALLY GOOD AT SCIENCE COME TO MY QUESTION PLEASEEEE Which fossil fuel create
Bas_tet [7]
Hey there!
The correct answer is C

Hope this helps you!

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6 0
4 years ago
gypsum is insoluble in water. you are asked to purify a sample of gypsum that is contaminated with a soluble salt.
katen-ka-za [31]

Answer:

a. The apparatus required to purify gypsum sample are: Bunsen burner, beaker, Filter Funnel, stirring rod, the filter paper.

b. Gypsum is a sulfate mineral that is made up of calcium sulfate dihydrate. Step-by-step instruction to purify gypsum sample is as follows:

1. Add water to the gypsum sample in a beaker.

2. Use the stirring rod to mix the mixture well.

3. Filter off the excess solid from the mixture using the filter paper and filter funnel.

4. Put the filtered mixture over the bunsen burner and evaporate the excess water from the mixture.

5. Allow the hot liquid to cool down and filter it again through the filter paper to get the pure gypsum.

7 0
3 years ago
A 0.08024 M solution of NaOH was used to titrate a solution of unknown concentration of HCl. A 32.08 mL sample of the HCl soluti
iris [78.8K]

Answer:

0.08024

Explanation:

4 0
3 years ago
What is the concentration of the unknown h3po4 solution? the neutralization reaction ish3po4(aq)+3naoh(aq)→3h2o(l)+na3po4(aq) -g
hjlf
First, we need to get moles of NaOH:

when moles NaOH = volume * molarity 

                                  = 0.02573L * 0.11 M

                                 = 0.0028 moles 

from the reaction equation:

H3PO4(aq) + 3NaOH → 3 H2O(l) + Na3PO4(aq)

we can see that when 1 mol H3PO4 reacts with→ 3 mol NaOH

 ∴ X mol H3PO4 reacts with → 0.0028 moles NaOH

∴ moles H3PO4 = 0.0028 mol / 3 = 9.4 x 10^-4 mol

now we can get the concentration of H3PO4:

∴[H3PO4] = moles H2PO4 / volume

               = 9.4 x 10^-4 / 0.034 L

               = 0.028 M
6 0
3 years ago
Read 2 more answers
Nault 25000L 250 our = 25000L 15040 8. How many grams of CaCl2 are needed to make 150.0 mL of a 0.500 M CF solution? (Note: CaCl
yuradex [85]

Answer:

You need 8,324 g of CaCl₂ yo make this solution

Explanation:

Molarity is a way to express concentration in a solution, in units of moles of solute per liter of solution.

To know the grams of CaCl₂ it is necessary to know, first, the moles of this substance with the desired volume and concentration , thus:

0,1500 L × \frac{0,500 mol}{L} = 0,075 CaCl₂ moles

Now, with the molar mass of CaCl₂ you will obtain the necessary grams, thus:

0,075 CaCl₂ moles  × \frac{110,98 g}{mol} = 8,324 g of CaCl₂

So, you need <em>8,324 g of CaCl₂</em> to make 150,0 mL of a 0,500M solution

I hope it helps!

3 0
3 years ago
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