2 × (atomic mass of Ag) + (atomic mass of Cl (
IT IS NOT POSSIBLE TO RETRIEVE A BOTTLE OF SULFATE BECAUSE SULFATE DOES NOT EXIST AS A DISTINCT CHEMICAL COMPOUND.
Sulphate is a polyatomic ion. A polyatomic ions refers to group of atoms that carry charges. Sulfate carries a charge of +2. Sulfate is a very reactive ion, thus, it can not be found existing on its own, it is always found in combination with other elements, such elements include H2SO4 and CaSO4.
Lithium cation and Lithium atom can be compared as follow;
<h3>
1) Charge:</h3>
The charge on Lithium atom is zero means, it has same number of protons and electrons. Hence, the nert effect is cancelled out and the atom gets zero charge.
On the other hand, Lithium cation is formed when it looses one electron. Therefore, the number of protons are greater by one number as compared to number of electrons resulting in the formation of +1 charge as shown below,
Li → Li⁺¹ + e⁻
<h3>
2) Size:</h3>
Secondly, Lithium atom has greater size as compared to Lithium cation because due to presence of greater number of protons compared to electrons in Lithium cation the nuclear charge appears to be greater as compared to neutral atom hence, pulling the valence electrons more effectively making the lithium cation smaller in size as compared to neutral atom.
<h3>
3) Reactivity:</h3>
We can also compare the reactivity of both species. The neutral will be more reactive than the charged atom because it is containing one valence electron and can donate it when ever it comes in contact with non-metals.
The volume of ethyl alcohol overflow will be 9.265mL.
To calculate the volume of ethyl alcohol overflow, we will use
∆V=V(á∆T)
Where,
∆V=volume expand
á=volumetric expansion Coefficients =0.00109/°C
V=initial volume =500ml
T'=final temp. =22°C
T=initial temp=5°C
Now,
∆V=500×(0.00109/°C) ×(22-5)
=500×(0.00109) (17)
=9.265ml
Thus, we find that the volume of ethyl alcohol overflow will be 9.265 mL.
learn more about ethyl alcohol:
brainly.com/question/11237501
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13 is the number for it on the periodic table and Group 3 is the correct answer hope this helps.
