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Arada [10]
3 years ago
12

Pleaseeeeee hellllllpppp

Chemistry
2 answers:
Yakvenalex [24]3 years ago
4 0
Im pretty Sure its B Tuesday And Wensday
Naddik [55]3 years ago
4 0
It's C.......... hope this helped
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Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.
Serjik [45]

I think the correct answer would be the last one.

7 0
2 years ago
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In your own words list and describe the three subatomic particles that make up atoms.
padilas [110]

Answer:

Subatomic particles making up an atom

Explanation:

Atom is the smallest unit of any matter

An atom consists of three subatomic particles - Protons, Neutrons, Electrons. Major atomic mass is in the nucleus ie a tiny deep area at the centre. Nucleus consists nucleons, which includes protons (positively charge) & neurons (neutrally charged). Negatively charged electrons are outside the central nucleus.

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2 years ago
Does gas have its own density
Leokris [45]

Answer:

The identity does not matter because the variables of Boyle's law do not identify the gas.

Explanation:

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2 years ago
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Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
Helppppppppppppppppppppppppp
bezimeni [28]
The awnser would be c i got you fam
7 0
3 years ago
Read 2 more answers
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