I've tried this like, probably 10 times, it never worksbut ig we'll see
Answer:
75 mg
Explanation:
We can write the extraction formula as
x = m/[1 + (1/K)(Vaq/Vo)], where
x = mass extracted
m = total mass of solute
K = distribution coefficient
Vo = volume of organic layer
Vaq = volume of aqueous layer
Data:
m = 75 mg
K = 1.8
Vo = 0.90 mL
Vaq = 1.00 mL
Calculations:
For each extraction,
1 + (1/K)(Vaq/Vo) = 1 + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62
x = m/1.62 = 0.618m
So, 61.8 % of the solute is extracted in each step.
In other words, 38.2 % of the solute remains.
Let r = the amount remaining after n extractions. Then
r = m(0.382)^n.
If n = 7,
r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg
m = 75 - 0.088 = 75 mg
After seven extractions, 75 mg (99.999 %) of the solute will be extracted.
Answer:
227 mL KBr
Explanation:
To find the amount of milliliters KBr, you need to (1) convert grams to moles (via molar mass from values on periodic table), then (2) find the amount of liters KBr (via molarity equation using molarity and moles), and then (3) convert liters to milliliters. The final answer should have 3 sig figs to match the amount of sig figs in the given values.
<u>(Step 1)</u>
Molar Mass (KBr): 39.098 g/mol + 79.904 g/mol
Molar Mass (KBr): 119.002 g/mol
17.2 grams KBr 1 mole
----------------------- x ------------------ = 0.145 moles KBr
119.002 g
<u>(Step 2)</u>
Molarity (M) = moles / volume (L)
0.640 M = 0.145 moles / volume
(0.640 M) x (volume) = 0.145 moles
volume = (0.145 moles) / (0.640 M)
volume = 0.227 L
<u></u>
<u>(Step 3)</u>
<u></u>
0.227 L KBr 1,000 mL
------------------ x ----------------- = 227 mL KBr
1 L
Answer:
d. can be separated into components
it's the answer and i hope it helps you
The answer is (3), oxidation occurs at the anode and reduction occurs at the cathode. That's because the oxidation reaction can lose electrons and reduction can gain electrons.
