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valkas [14]
3 years ago
13

Which equation represents the reaction of acetic (ethanoic) acid with water? A. CH3COO- + H2O CH3COOH + OH- B. CH3COOH + H2O CH3

COO- + H3O+ C. CH3COO- + H2O CH3COO2- + H3O+ D. CH3COOH + H2O CH3COOH2+ + OH-
Chemistry
1 answer:
Leno4ka [110]3 years ago
8 0
"CH3COOH + H2O CH3COO- + H3O+" is the equation among the choices given in the question <span>represents the reaction of acetic (ethanoic) acid with water. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.</span>
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Mandarinka [93]

Answer:

3. The temperatures of the two substances equalize.

Explanation:

  • As two objects at different temperatures are placed in contact, heat is transferred from the warmer to the cooler object until the temperature of the two objects be the same.
  • The amount of heat that is transferred from the warmer object is equal to the amount of heat that is transferred into the cooler object.
  • This is in agreement with the law of conservation of energy.
  • <em>So, the right choice is: 3. The temperatures of the two substances equalize. </em>

<em></em>

8 0
4 years ago
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What are acids? List few substances containing acid.
Gelneren [198K]
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3 0
2 years ago
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5 properties of acids
Dahasolnce [82]

Answer:

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   They convert the color of Methyl Orange from Orange/Yellow to Pink.

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   Acids can conduct electricity.

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Explanation:

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8 0
3 years ago
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CaHeK987 [17]

Answer:

Q = 30355.2 J

Explanation:

Given data:

Mass of ice = 120 g

Initial temperature = -5°C

Final temperature = 115°C

Energy required = ?

Solution:

Specific heat capacity of ice is = 2.108 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT = T2 -T1

ΔT = 115 - (-5°C)

ΔT = 120 °C

Q = 120 g × 2.108 j/g.°C × 120 °C

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4 years ago
Convert 1.45 × 1024 atoms of carbon to moles of carbon.
anygoal [31]
1 mol = 6.02 * 10^23 atoms of carbon
x mol = 1.45 * 10^24 atoms of carbon

1/x =6.02*10^23 / 1.45 * 10^24

6.02 * 10^23 x = 1.45 * 10^24
x = 1.45 * 10^24 / 6.02 * 10^23
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8 0
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