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Ann [662]
3 years ago
11

According to the VSEPR theory, what is the shape of a molecule that has a central atom bound to three other atoms with no lone p

airs of electrons?
Chemistry
2 answers:
steposvetlana [31]3 years ago
8 0

Explanation:

A molecule which contains three bond pairs but no lone pair of electrons will have a trigonal planar geometry.

Hybridization of such a geometry is sp^{2}.

For example, BF_{3} is a trigonal planar molecule.

As, hybridization of BF_{3} will be calculated as follows.

                Hybridization = \frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

              Hybridization = \frac{1}{2}[V+N-C+A]

                                    = \frac{1}{2}[3 + 3]

                                    = 3

So, the hybridization of BF_{3} will be sp^{2}. As there are 3 bond pairs and no lone pair of electrons. Hence, the geometry of BF_{3} is trigonal planar.

Thus, we can conclude that according to the VSEPR theory, the shape of a molecule that has a central atom bound to three other atoms with no lone pairs of electrons is trigonal planar.

VikaD [51]3 years ago
4 0
Triangular planar structure
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