1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lana71 [14]
3 years ago
13

sucrose is composed of carbon hydrogen and oxygen which of the following is not needed in order to determine the precent by mass

of three elements
Chemistry
1 answer:
Dimas [21]3 years ago
3 0

Explanation:

It is often desirable to determine the mass percent of elements in a given compound.

To determine the mass percent of elements:

  • Evaluate the formula mass of the compound. This is done by summing the atomic masses of the atoms in the compound together.
  • The mass percentage is determined by pacing the mass contribution of each element or group to the formula mass of the compound and multiply by 100.

Learn more:

Percent by mass brainly.com/question/5544078

#learnwithBrainly

You might be interested in
If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0
2 years ago
Is aluminum foil an element, compound or mixture
lora16 [44]
It is an element. Aluminun foil is aluminum prepared in thin leaves.
3 0
3 years ago
Read 2 more answers
Which group will have a charge of +2 when ionized?
inysia [295]

Answer:

Alkaline earth metals

Explanation:

Group 2 has 2 valence electrons that they lose when being ionized, thus making  their charge 2+.

5 0
2 years ago
Read 2 more answers
Predict the bond angle in metgane using vsepr theory
inessss [21]
Bond Angle in the molecule of Methane according to the VSEPR theory is that it has a bond angle of 109.5 degrees with respect to the Carbon and the Hydrogen
6 0
3 years ago
Will the scientific method be different 100 years from now ? Why or why not?
sveta [45]
NO, it should not be the process is still the same . the only factors about it that should change is the experiment itself.:)
5 0
3 years ago
Read 2 more answers
Other questions:
  • What is a group of atoms bonded together
    10·2 answers
  • Which equation represents the oxidation half-reaction for this redox reaction?
    9·1 answer
  • Explain why we would only ever see a full moon at night
    11·1 answer
  • Which sequence represents the relationship between temperature and volume as explained by the kinetic-molecular theory?
    5·1 answer
  • As chief chemist at Superior Analytical Products (SAP) you must design an experiment to determine the density of an unknown liqu
    15·1 answer
  • What is the chemical composition of bituminous coal?
    10·1 answer
  • Hi there! could someone help with this? its due today.
    12·2 answers
  • Physical reactions of carbonyl group​
    7·1 answer
  • Calculate the percent error in the atomic weight if the mass of a Cu electrode increased by 0.4391 g and 6.238x10-3 moles of Cu
    15·1 answer
  • An ideal gas is made up of gas particles that...
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!