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skad [1K]
3 years ago
12

Mrs. LaCross leaves school and accidentally leaves her coffee mug on the roof of her car as shown in the picture below.

Physics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

When she stops at a fast pace the energy and wind will take the cup forward and it will most likeley brake

Explanation:

I'm not entirely sure this is what you were looking for but I hope this helped!

PLEASE MARK ME AS BRAINLIEST

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Over 4 seconds, a car's momentum decreases by 1000 kg m/s how much force did it take to make this happen?
kotykmax [81]

Answer:

250N

Explanation:

Given parameters:

Time  = 4s

Momentum  = 1000kgm/s

Unknown:

Force  = ?

Solution:

To solve this problem, we use Newton's second law of motion;

      Ft  = Momentum

F is the force

t is the time

So;

          F x 4 = 1000kgm/s

          F  = 250N

6 0
3 years ago
A nurse pushes a cart by exerting a force on the handle at a downward angle of 36 degrees below the horizontal. the loaded cart
Troyanec [42]

Since it was stated that it must move at constant velocity, so the only force it must overpower is the frictional force.

So the equation is:

F cos θ = Ff

F cos 36 = 65 N

F = 80.34 N

 

<span>So the nurse must exert 80.34 N of force</span>

4 0
3 years ago
A 500 kg car traveling at 20 m/s rear ends another car of 600 kg at rest. The collision is great enough that the two cars stick
aksik [14]

Answer: its 50

Explanation:

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4 0
3 years ago
Which word in the following sentence should be capitalized in order to follow the conventions of Standard English?
Monica [59]
Being that Alaska is a state, it should be capitalized. You always capitalize a state name
3 0
3 years ago
What is the temperature of a sample of gas when the average translational kinetic energy of a molecule in the sample is 8.37 × 1
-BARSIC- [3]

Answer:

404K

Explanation:

Data given, Kinetic Energy.K.E=8.37*10^-21J

Note: as the temperature of a is increase, the rate of random movement will increase, hence leading to more collision per unit time. Hence we can say that the relationship between the kinetic energy and the temperature is a direct variation.

This relationship can be expressed as

K.E=\frac{3}{2}KT

where K is a constant of value 1.38*10^-23

Hence if we substitute the values, we arrive at

T=\frac{2/3(8.37*10^{-21})}{1.38*10^-23}\\ T=404K

converting to degree we have 131^{0}C

4 0
3 years ago
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