What is the temperature of a sample of gas when the average translational kinetic energy of a molecule in the sample is 8.37 × 1
1 answer:
Answer:
404K
Explanation:
Data given, Kinetic Energy.K.E=8.37*10^-21J
Note: as the temperature of a is increase, the rate of random movement will increase, hence leading to more collision per unit time. Hence we can say that the relationship between the kinetic energy and the temperature is a direct variation.
This relationship can be expressed as
where K is a constant of value 1.38*10^-23
Hence if we substitute the values, we arrive at
converting to degree we have
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Answer:
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Explanation:
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p₀ = 0
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p₀ =
0 = M v + m
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= - M / m v
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