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Misha Larkins [42]
3 years ago
12

Although the skier has a jacket on, she is still cold. How can her circulatory system help keep her warm?

Physics
2 answers:
Pepsi [2]3 years ago
6 0

by creating body heat so she can stay warm

Nadya [2.5K]3 years ago
4 0
She needs body heat to keep her warm.
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An 8.2 kg object accelerates at 8.0 m/s^2. What is the acceleration?
ZanzabumX [31]

Answer:

8.0m/s²

Explanation:

meters per second squared is a unit of acceleration so 8.0m/s² is the answer

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2 years ago
Calculate the mass of a block of ice having volume 5 m cube. (density of ice= 920 kg/m cube)​
GarryVolchara [31]

Answer:

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PLS HELP WILL MARK BRAINLIEST IF RIGHT NEED IMMEDIATELY PLEASEEEEE
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A laser beam is incident at an angle of 30.0° from the vertical onto a solution of corn syrup in water. The beam is refracted to
dimaraw [331]

Answer with Explanation:

We are given that

Angle of incidence,i=30^{\circ}

Angle of refraction,r=19.24^{\circ}

a.Refractive index of air,n_1=1

We know that

n_2sinr=n_1sini

n_2=\frac{n_1sin i}{sin r}=\frac{sin30}{sin19.24}=1.517

b.Wavelength of red light in vacuum,\lambda=632.8nm=632.8\times 10^{-9} m

1nm=10^{-9} m

Wavelength in the solution,\lambda'=\frac{\lambda}{n_2}

\lambda'=\frac{632.8}{1.517}=417nm

c.Frequency does not change .It remains same in vacuum and solution.

Frequency,\nu=\frac{c}{\lamda}=\frac{3\times 10^8}{632.8\times 10^{-9}}

Where c=3\times 10^8 m/s

Frequency,\nu=4.74\times 10^{14}Hz

d.Speed in the solution,v=\frac{c}{n_2}

v=\frac{3\times 10^8}{1.517}=1.98\times 10^8m/s

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3 years ago
momentum A proton interacts electrically with a neutral HCl molecule located at the origin. At a certain time t, the proton’s po
arlik [135]

Answer:

\ m/s

Explanation:

F = Force =

m = Mass of proton = 1.7\times 10^{-27\ kg

t = Time taken = 2\times 10^{-14}\ s

Acceleration is given by

a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{}{1.7\times 10^{-27}}\\\Rightarrow a=\ m/s^2

v=u+at\\\Rightarrow v=+\times 2\times 10^{-14}\\\Rightarrow v=+\times 2\times 10^{-14}\\\Rightarrow v=+\\\Rightarrow v=\ m/s

The velocity of the proton is \ m/s

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