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2 years ago

Over 4 seconds, a car's momentum decreases by 1000 kg m/s how much force did it take to make this happen?

Physics

1 answer:

kotykmax [81]2 years ago

6 0

Answer:

250N

Explanation:

Given parameters:

Time = 4s

Momentum = 1000kgm/s

Unknown:

Force = ?

Solution:

To solve this problem, we use Newton's second law of motion;

Ft = Momentum

F is the force

t is the time

So;

F x 4 = 1000kgm/s

F = 250N

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A stream of warm water is produced in a steady-flow mixing process by combining 1.0 kg/s of cool water at 25 °C with 0.8 kg/s of

Tamiku [17]

Explanation:

The given data is as follows.

$m_{1}$ = 0.8 kg/s = 800 g, $C_{1} = 4.18 J/g^{o}C$

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$T_{2}$ = T - 25

Now, according to the law of conservation of energy,

$m_{1}C_{1}T_{1} = m_{2}C_{2}T_{2} + mL$

$800 \times 4.18 \times (75 - T) = 1000 \times 4.18 \times (T - 25)$ + 30000

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3 years ago

How many drops of water are in a 1.0 L bottle? (Hint: Start by estimating the diameter of a drop of water.)

o-na [289]

Answer:

N = 2000 drops approx with 1 cm diameter each

Explanation:

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so volume of one drop is given by

$V = \frac{1}{6}\pi d^3$

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so we have

$1L = 10^{-3} m^3$

now we have

$N = \frac{10^{-3}}{0.53 \times 10^{-6}}$

$N = 2\times 10^3$

so it will have approx 2000 drops in it with diameter 1 cm each drop

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