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11Alexandr11 [23.1K]
3 years ago
12

Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value.

Chemistry
1 answer:
frez [133]3 years ago
6 0
The correct response is the second option.
6.1103x10^4. As this was the only answer that had the same number of significant figures as the starting value.
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Solve pls brainliest
inna [77]

Answer:

Explanation:

The two green substances are not the same.  Most of their properties are different, except some are alike.  Since not all of their properties are matching, they are not the same substance.

I am not sure if this is what you were looking for, but if it is then I am happy to help.  

7 0
2 years ago
Mara and ivy are asked to identify two minerals in science class. To do this, they decided to study the physical properties of t
scZoUnD [109]

Answer:

2 only is a pretty accurate answer the others dont make sense  to me.

Explanation:

8 0
3 years ago
Read 2 more answers
Find the mass of 175.4mL of benzene if the density is 0.8786g/ml
bulgar [2K]
Hey there!:

Volume = 175.4 mL

density = 0.8786 g/mL  

mass = ?

Therefore:

D = m / V

0.8786 = m / 175.4

m = 0.8786 * 175.4

m = 154.10644 g

hope this helps!


5 0
3 years ago
How do you draw the structure of 5-iodo-2-methoxyhexane?
monitta
The structure is in attachment.
Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds<span> are </span>single) <span>of six </span>carbon atoms. Methoxy<span> group is the functional group consisting of a methyl group bound to oxygen. Iodo is substituent consists of ionide (element in 17 periodic group).</span>
Download docx
8 0
3 years ago
Read 2 more answers
A scuba tank has a pressure of 195 KPa at a temperature of 10 °C. The volume of the tank is 350 L. How many grams of air is in t
marissa [1.9K]

The mass of air in the scuba tank is 841.614 g.

Using the ideal gas equation;

PV=nRT

P = pressure of the gas = 195 kPa

V = volume of the gas =  350 L

n = Number of moles of the gas = ??

R = molar gas constant = R = 8.314 J K-1 mol-1

T = temperature of the gas =  10 °C or 283 K

n = PV/RT

n = 195 * 350/8.314 * 283

n = 68250/2352.862

n = 29.00 moles

Number of moles = mass/molar mass

mass of air = Number of moles * molar mass

mass of air = 29.00 moles * 29g/mol

Mass of air = 841.614 g

Learn more: brainly.com/question/4147359

5 0
3 years ago
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