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DedPeter [7]
3 years ago
9

A 0.57 kg rubber ball has a speed of 1.2 m/s at point A and kinetic energy 7.5 J at point B. Find a) the ball’s kinetic energy a

t A.(b) What is its speed at point B?(c) What is the total work done on the particle as it moves fromA to B?
Physics
1 answer:
worty [1.4K]3 years ago
6 0

Answer:

Explanation:

mass m = .57 kg

speed at A ( v₁ ) = 1.2 m /s

a )

kinetic energy at A

= 1/2 x mass x velocity

= 1/2 x .57 x (1.2)²

= .41 J

b ) Let speed at B be v₂

given that

1/2 m x v₂² = 7.5

.5 x .57 v₂² = 7.5

v₂ = 5.13 m/s

c ) Work done on the particle  as it moves from A to B

= increase in kinetic energy

= 7.5 - .41

= 7.09 J

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Research shows that Mount Everest Grows an Average of 4 millimeters each year. How many will it take to grow 720 millimeters.?
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Diagnostic ultrasound of frequency 3.82 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such
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Explanation:

It is given that,

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(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁

i.e. \lambda=\dfrac{v}{\nu}

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\lambda_1=0.089\ m

(b) If the speed of sound in tissue is 1650 m/s .

\lambda_2=\dfrac{v}{\nu}

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Was the cannonball able to hit its target of 50 meters when the initial velocity was 20 m/s? Why?/Why Not?
frosja888 [35]

Answer:

The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Explanation:

From the question given above, the following data were obtained:

Height to which the target is located = 50 m

Initial velocity (u) = 20 m/s

To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 20² – (2 × 10 × h)

0 = 400 – 20h

Collect like terms

0 – 400 = – 20h

– 400 = – 20h

Divide both side by – 20

h = – 400 / – 20

h = 20 m

Thus, the the maximum height to which the cannon ball attained is 20 m.

From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

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2 years ago
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