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DedPeter [7]
3 years ago
9

A 0.57 kg rubber ball has a speed of 1.2 m/s at point A and kinetic energy 7.5 J at point B. Find a) the ball’s kinetic energy a

t A.(b) What is its speed at point B?(c) What is the total work done on the particle as it moves fromA to B?
Physics
1 answer:
worty [1.4K]3 years ago
6 0

Answer:

Explanation:

mass m = .57 kg

speed at A ( v₁ ) = 1.2 m /s

a )

kinetic energy at A

= 1/2 x mass x velocity

= 1/2 x .57 x (1.2)²

= .41 J

b ) Let speed at B be v₂

given that

1/2 m x v₂² = 7.5

.5 x .57 v₂² = 7.5

v₂ = 5.13 m/s

c ) Work done on the particle  as it moves from A to B

= increase in kinetic energy

= 7.5 - .41

= 7.09 J

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Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

8 0
3 years ago
A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has
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Answer:

r = 0.5 m

Explanation:

First we find the angular speed of the ball by using its period:

ω = θ/t

For the time period:

ω = angular speed = ?

θ = angular displacement = 2π rad

t = time period = 0.5 s

Therefore,

ω = 2π rad/0.5 s

ω = 12.56 rad/s

Now, for the radius:

v = rω

r = v/ω

where,

v = linear speed = 6.29 m/s

r = radius = ?

r = (6.29 m/s)/(12.56 rad/s)

<u>r = 0.5 m</u>

8 0
3 years ago
If the velocity of an object is doubled, its kinetic energy is ______
swat32
Increased by a factor of 4
4 0
3 years ago
A positively charged plastic ruler is brought close to a piece paper resting on the desk. The piece of paper was initially neutr
stealth61 [152]

Answer: static electricity

Explanation:

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4 0
3 years ago
A 48 kg cart is sitting motionless at the top of the hill. At what height, did the cart start at, to reach 88435 J of energy at
svet-max [94.6K]

Answer : The height is 188 meters  

Explanation :   When the cart reached at the end from top of hill then the cart have potential energy .

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7 0
3 years ago
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