All categories

3 years ago

What is the kinetic energy of a 74.0 kg skydiver falling at a terminal velocity of 52.0m/s?

Physics

1 answer:

skad [1K]3 years ago

8 0

Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

You might be interested in

Convert 13.6g/cm3 into kg/m3

Wewaii [24]

Answer:

0.000136kg/m3

Explanation:

13.6 / 1000 = 0.0136kg/cm3

0.0136 / 100 = 0.000136kg/m3

5 0

3 years ago

The Hoover dam is a hydroelectric power plant that converts the energy of falling water into electricity. Which of the following

vlabodo [156]

The correct answer to the question is : B) The weight of the water, and C) The height of the water.

EXPLANATION :

Before coming into any conclusion, first we have to understand potential energy of a body.

The potential energy of a body due to its position from ground is known as gravitational potential energy.

The gravitational potential energy is calculated as -

Potential energy P.E = mgh

Here, m is the mass of the body, and g is the acceleration due to gravity.

h stands for the height of the body from the ground.

We know that weight of a body is equal to the product of mass with acceleration due to gravity.

Hence, weight W = mg

Hence, potential energy is written as P.E = weight × height.

Hence, potential energy depends on the weight and height of the water.

3 0

4 years ago

Read 2 more answers

A beam of electrons moving in the x-direction enters a region where a uniform 208-G magnetic field points in the y-direction. Th

GREYUIT [131]

Answer:

$1.26\cdot 10^7 m/s$

Explanation:

When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:

$F=qvB$

where

q is the charge

v is its velocity

B is the strength of the magnetic field

Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:

$qvB=m\frac{v^2}{r}$

where

m is the mass of the particle

r is the radius of the orbit of the particle

The equation can be re-arranges as

$v=\frac{qBr}{m}$

where in this problem we have:

$q=1.6\cdot 10^{-19}C$ is the magnitude of the charge of the electron

$B=208 G=208\cdot 10^{-4}T$ is the strength of the magnetic field

The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,

$r=3.45 mm = 3.45\cdot 10^{-3} m$

$m=9.11\cdot 10^{-31} kg$ is the mass of the electron

So, the electron's speed is

$v=\frac{(1.6\cdot 10^{-19})(208\cdot 10^{-4})(3.45\cdot 10^{-3})}{9.11\cdot 10^{-31}}=1.26\cdot 10^7 m/s$

6 0

3 years ago

Which of the following has the largest inertia?

Shkiper50 [21]

Option D, a semi truck parked in a parking lot

Reason: Inertia is the state of a body which needs a force to come into the act of motion.

The more massive the object is the more is its inertia.

5 0

3 years ago

The electric field everywhere on the surface of a thin, spherical shell of radius 0.800 m is of magnitude 902 N/C and points rad

Lilit [14]

Explanation:

(a) From E=

(8.99×10

N⋅m

)

(8.90×10

N/C)(0.750m)

=5.57×10

−8

But Q is negative since

→

points inward, so

Q=−5.57×10

−8

C=−55.7nC

(b) The negatve charge has a spherically symmetric charge distribution, concentric with the spherical shell

8 0

3 years ago