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Paraphin [41]
3 years ago
6

What is the kinetic energy of a 74.0 kg skydiver falling at a terminal velocity of 52.0m/s?

Physics
1 answer:
skad [1K]3 years ago
8 0

Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

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tigry1 [53]

Answer:

Q/4πε0 [1/R - 1/√R2+d2]

Explanation:

Q/4πε0 [1/R - 1/√R2+d2] is the answer

explanation is attached.

toppr

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2 years ago
What should you do before inserting a wire into an outlet box?
Westkost [7]

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I think D it could maybe B

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2 years ago
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A 125 g pendulum bob hung on a string of length 35 cm has the same period as when the bob is hung from a spring and caused to os
Bingel [31]

Answer:

k = 3.5 N/m

Explanation:

It is given that the time period the bob in pendulum is the same as its time period in spring mass system:

Time\ Period\ of\ Pendulum = Time\ Period\ of\ Spring-Mass\ System\\2\pi \sqrt{\frac{l}{g}} = 2\pi \sqrt{\frac{m}{k}

\frac{l}{g} = \frac{m}{k}\\\\ k = g\frac{m}{l}

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m = mass of bob = 125 g = 0.125 kg

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k = (9.81\ m/s^2)(\frac{0.125\ kg}{0.35\ m})\\\\

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4 0
3 years ago
A potential difference of 24 V is applied to a 150-ohm resistor. How much current flows through the resistor?​
Lady_Fox [76]

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Potential Difference (v) = 24 V

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3 0
2 years ago
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nata0808 [166]

Answer:

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Explanation:

Given that

m = 40 kg

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K=1000

Given that kinetic energy(K) varies with mass(m) and velocity(v)

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Where

C= Constant

m=mass

v=velocity

When

m = 40 kg ,v= 15 m/s ,K=1000

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1000 = C( 40 x 15²)

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When m = 40 kg and v= 20 m/s

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K= 0.1111 x (40 x 20²)

K' = 1777.777  J

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3 years ago
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