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4 years ago

QUESTION 1

Physics

2 answers:

Morgarella [4.7K]4 years ago

7 0

Answer:

1. c.There are areas in California that use the heat from deep in the Earth to generate electricity.

2. c.Natural gas is a great alternative to electricity for cooking.

3. d.Solar panels are able to gather the energy from the sun and convert it into electrical energy.

4. b.My town is powered by electricity that is generated by the energy from the flow of water through a large dam.

5. d.There are drilling platforms all along the coast that are used to drill for natural gas that can be used to generate electricity.

Explanation:

c. Heat generated deep into the earth is called Geothermal Energy. This heat is carried out of the earth crust in the form of water or steam.

c. Natural gas is obtained from the hydrocarbon reservoirs in the huge rocks of the deeper earth crust. It is associated with the reservoirs of the in-earth fossil fuels.

d. Solar energy is a form of renewable energy that can be harnessed for various utilities. Renewable energy is that energy which will never deplete as a resource or their rate of formation is faster than its usage.

b. Water head is raised by collection of water from the flowing water reservoir and this is channeled through a regulated passages as per the requirement to run the turbine connected to an alternator via a shaft to produce electricity.

d. Natural gas is gaseous product obtained along with the fossil fuels and depletes sooner whereas its regeneration takes thousands of years.

brilliants [131]4 years ago

5 0

1). (c). The heat from deep in the Earth is the renewable resource.

2). (c). The natural gas is the non-renewable resource.

3). (d). The energy from the sun, collected with solar panels, is the renewable resource.

4). (b). The energy in the flow of water through the dam is the renewable resource. If you analyze it in detail, it turns out to be solar energy.

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3 years ago

Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medic

Elena-2011 [213]

Answer:

1.1 x 10^9 ohm metre

Explanation:

diameter = 1.5 mm

length, l = 5 cm

Potential difference, V = 9 V

current, i = 230 micro Ampere = 230 x 10^-6 A

radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m

Let the resistivity is ρ.

Area of crossection

A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2

Use Ohm's law to find the value of resistance

V = i x R

9 = 230 x 10^-6 x R

R = 39130.4 ohm

Use the formula for the resistance

$R=\rho \frac{l}{A}$

$\rho =\frac{RA}{l}$

$\rho =\frac{39130.4\times 0.05}{1.766\times 10^{-6}}$

ρ = 1.1 x 10^9 ohm metre

Explanation:

7 0

3 years ago

Three wires meet at a junction. wire 1 has a current of 0.40 aa into the junction. the current of wire 2 is 0.73 aa out of the j

Mnenie [13.5K]

The magnitude of the current in wire 3 is (I₃)= 0.33A

<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>

To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,

I₁ + I₂ + I₃ = 0

Where we are given,

I₁ = current in wire 1

=0.40 A.

I₂ = current in wire 2

= -0.73 A.

We have to calculate the magnitude of the current in wire 3, I₃

Now we put the known values in above equation, we get,

I₁ + I₂ + I₃ = 0

Or, I₃ = -.(I₁ + I₂)

Or, I₃ = -.(0.40 - 0.73)

Or, I₃ = 0.33 A

From the above calculation, we can conclude that the current in wire 3 is I₃ = 0.33 A

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7 0

1 year ago

If the moon is half full on November 2, on approximately what date will it next become full?

anyanavicka [17]

The complete cycle of lunar phases has a period of 29.531 days.

You've described two phases that are separated by 1/4 of the
complete cycle.

If the moon is exactly at First Quarter (half-full and getting bigger)
at, let's say, 12:00 Noon on November 2 where you are, then it will
be Full after

29.531 days / 4 = 7 days 9 hours 11 minutes .

That's 9:11 PM on November 9 .

7 0

4 years ago

Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen

xxTIMURxx [149]

Answer:

A) first laser

B) 0.08m

C) 0.64m

Explanation:

To find the position of the maximum you use the following formula:

$y=\frac{m\lambda D}{d}$