Three wires meet at a junction. wire 1 has a current of 0.40 aa into the junction. the current of wire 2 is 0.73 aa out of the j
1 answer:
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Answer:
3658.24m
Explanation:
Hello!
the first thing that we must be clear about is that the train moves with constant acceleration
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf = final speed =160km/h=44.4m/s
Vo = Initial speed =42.9km/h=11.92m/s
A = acceleration =0.25m/s^2
X = displacement
solving
the distance traveled by the train is 3658.24m
The speed of a electron that is accelerated from rest through an electric potential difference of 120 V is
We know, that the energy of the system is always conserved.
Using the Law of Conservation of energy,
U=0
Here, K is the kinetic energy and U is the potential energy.
Now, substituting the formula of U and K, we get:
=0------(1)
Here,
m is the mass of the electron
v is the speed of the electron
q is the charge on the electron
V is the potential difference
Let and
represent the final and initial speed.
Here, =0
Solving for , we get:
=6.49m/s
To learn more about the conservation of energy, refer to:
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