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svetlana [45]
3 years ago
6

. At a frequency ω1, the reactance of a certain capacitor equals that of a certain inductor.

Physics
2 answers:
leva [86]3 years ago
8 0

Answer:

Part a)

ratio = 4

reactance of inductor will be more

Part b)

ratio = 1/9

reactance of capacitor will be more

Explanation:

As we know that at angular frequency ω1 the reactance of capacitor is equal to the reactance of inductor

so here we can say that this angular frequency must be resonance frequency

so we will have

x_L = x_C

now we will have

part a)

if we have another frequency

\omega_2 = 2\omega_1

so here in this case

x_L = 2\omega_1 L

x_C = \frac{1}{2\omega_1C}

now the ratio of the new reactance is given as

ratio = \frac{2\omega_1L}{\frac{1}{2\omega_1C}}

ratio = 4

so reactance of inductor will be larger in this case

part a)

if we have another frequency

\omega_3 = \frac{\omega_1}{3}

so here in this case

x_L = \frac{\omega_1}{3} L

x_C = \frac{3}{\omega_1C}

now the ratio of the new reactance is given as

ratio = \frac{\frac{\omega_1}{3}L}{\frac{3}{\omega_1C}}

ratio = \frac{1}{9}

so reactance of capacitor will be larger in this case

xeze [42]3 years ago
5 0
The answer to the set of questions are as follows:

a. 2 ( 2/w2C) = 4xc2 = Xl2 / Xc2 = 4
<span>
The inductors reactance is greater than the capacitor

b. </span>(1/ 3w1C ) = (1/ 9w3C ) = 1/9 Xc3 = X l2/ Xc2 = 1/9
<span>
The capacitors reactance is greater than inductor

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
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