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Hatshy [7]
3 years ago
10

Do blood cells have a rigid of cells walls

Chemistry
1 answer:
KatRina [158]3 years ago
4 0

<em>Yes</em> the blood cells have a rigid of cell walls as their cell walls are cell membrane.

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Convert 25 gigaseconds into centiseconds​
dangina [55]

25 gigaseconds is equal to 2,500,000,000,000 centiseconds

6 0
3 years ago
What two elements are commonly found in Mica, Quartz and Feldspar? Explain your answer.
kifflom [539]

Answer:

oxygen and silicon, both are common

6 0
3 years ago
Nvm i have to answer lol
DIA [1.3K]

Answer:

i will do a joke... hmmm...

Explanation:

why did the nurse need a red pen?

To draw out blood. lol

5 0
3 years ago
Read 2 more answers
Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What i
g100num [7]
It's simple, just follow my steps.

1º - in 1 L we have 0.0100~g of BaCO_3

2º - let's find the number of moles.

\eta=\frac{m}{MM}

\eta=\frac{0.0100}{197.3}

\boxed{\boxed{\eta=5.07\times10^{-5}~mol}}

3º - The concentration will be

C=5.07\times10^{-5}~mol/L

But we have this reaction

BaCO_3\rightleftharpoons Ba^{2+}+CO_3^{2-}

This concentration will be the concentration of Ba^{2+}~~and~~CO_3^{2-}

K_{sp}=\frac{[Ba^{2+}][CO_3^{2-}]}{[BaCO_3]}

considering [BaCO_3]=1~mol/L

K_{sp}=[Ba^{2+}][CO_3^{2-}]

and

[Ba^{2+}]=[CO_3^{2-}]=5.07\times10^{-5}~mol/L

We can replace it

K_{sp}=(5.07\times10^{-5})*(5.07\times10^{-5})

K_{sp}\approx25.70\times10^{-10}

Therefore the K_{sp} is:

\boxed{\boxed{\boxed{K_{sp}\approx2.57\times10^{-11}}}}
4 0
3 years ago
Read 2 more answers
8. If I have 34 grams of FeO, how many grams of Oxygen were synthesized?<br>Fe + O2 → Feo​
krek1111 [17]

Answer:

34 gram of FeO produced 8 gram of oxygen.

Explanation:

Given data:

Mass of FeO = 34 g

Mass of oxygen = ?

Solution;

Chemical equation:

2FeO → 2Fe + O₂

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 34 g /71.8 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of FeO with oxygen:

             FeO       :       O₂

                2         :        1

                0.5      :      1/2 × 0.5 = 0.25

Mass of oxygen:

Mass = number of moles × molar mass

Mass =  0.25 mol × 32 g/mol

Mass = 8 g

So 34 gram of FeO produced 8 gram of oxygen.

8 0
3 years ago
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